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satela [25.4K]
3 years ago
10

What is the area of 71 length and 27 width of the triangle??

Mathematics
1 answer:
vazorg [7]3 years ago
8 0
The area of this triangle is 958.5 units^2
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NEED URGENT HELP!! WILL GIVE BRAINLIEST
Flauer [41]

1. You need to multiply the denominator by something that will make the content of the radical be a square—so that when you take the square root, you get something rational. Easiest and best is to multiply by √6. Of course, you must multiply the numerator by the same thing. Then simplify.

\displaystyle\frac{2}{\sqrt{6}}=\frac{2}{\sqrt{6}}\cdot\frac{\sqrt{6}}{\sqrt{6}}\\\\=\frac{2\sqrt{6}}{\sqrt{6}\cdot\sqrt{6}}=\frac{2\sqrt{6}}{6}\\\\=\bf{\frac{\sqrt{6}}{3}}

2. Identify the squares under the radical and remove them.

5\sqrt{12xm^3}=5\sqrt{(4m^2)(3xm)}=5\sqrt{(2m)^2}\sqrt{3xm}\\\\=5\cdot 2m\sqrt{3xm}=\bf{10m\sqrt{3xm}}

7 0
3 years ago
Read 2 more answers
Is the sum even or odd? 6+7
valentina_108 [34]
Odd.................................

4 0
2 years ago
Help ???????????????????????
Likurg_2 [28]

Answer:

I dont remember how to do this but i wish you luck, try searching on khan academy for how to do this ;)

Step-by-step explanation:

5 0
3 years ago
Determine if y varies directly with x. Give the constant of variation, when appropriate. (picture below)
maxonik [38]

Based on the given variation, y does not vary directly with x and the constant of variation are 8, 3.2 and 1.25 respectively.

<h3>Variation</h3>

y = k × x

where,

k = constant of proportionality

y = -40

x = -5

y = k × x

-40 = k × -5

-40 = -5k

k = -40/-5

k = 8

when,

y = 8 and x = 2.5

y = k × x

8 = k × 2.5

8 = 2.5k

k = 8/2.5

k = 3.2

when,

y = 5 and x = 4

y = k × x

5 = k × 4

5 = 4k

k = 5/4

k = 1.25

Learn more about variation:

brainly.com/question/6499629

#SPJ1

5 0
1 year ago
URGENT PLEASE HELP ME!!
Andrews [41]

Answer:

D  2400 ft^2

Step-by-step explanation:

His joumey maps out a right angles triangle with base 80 and height 60.

The required area = 1/2 * 80 * 60

= 2400 ft^2

4 0
2 years ago
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