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3 years ago

What is the length of a line segment that extends from (-3 , 4) to (4, 4)?

Mathematics

2 answers:

jeka57 [31]3 years ago

6 0

Answer:

the distance is 7

Step-by-step explanation:

Use the distance formula:

d=√ (4−(−3))2+(4−4)2

PolarNik [594]3 years ago

4 0

Answer:

Step-by-step explanation:

using the distance formula

√(4- -3)^2 + (4-4)^2

√49

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im so sad i literally cried for 10 min straight because i have three 70's on my grade progress report and my mom only wants 80's

givi [52]

Answer:

You shouldn't blame your mom. You are more than capable of getting 80's that is the bare minimum. Your mom does not want you to fail, try harder and get better grades. 70's are not the best

7 0

3 years ago

Charmaine has 360 acres of land. She planted 5/8 of the land with corn. How many acres did she plant with corn?

makkiz [27]

Answer: 225

Step-by-step explanation:

Fraction = numerator/denominator

numerator = ×

denominator = ÷

So,

5/8

numerator : 5

denominator : 8

360.5/8 = 1800/8 = 225

Have a nice day!

8 0

3 years ago

Read 2 more answers

Math help plz! marking brainliest

nirvana33 [79]

Answer:

Step-by-step explanation:

200 miles

8 0

3 years ago

Find the difference. Enter your answer in lowest terms in the box below as a

lara [203]

Answer:

76/165

Step-by-step explanation:

The difference of fractions can be found using the formula ...

a/b -c/d = (ad -bc)/(bd)

<h3>Difference</h3>

Using the given values in the formula, we have ...

$\dfrac{8}{11}-\dfrac{4}{15}=\dfrac{8(15)-11(4)}{11\cdot15}=\dfrac{120-44}{165}=\boxed{\dfrac{76}{165}}$

Here, the difference fraction does not need to be reduced. Many calculators and spreadsheets can do this arithmetic for you.

The above formula can also be used for sums of fractions. In that case, the sign changes from minus to plus.

7 0

2 years ago

F(x)=e*1/x<br>Calculate f'(x)

Murljashka [212]

Answer:

$\huge\boxed{f'(x)=-\dfrac{e^\frac{1}{x}}{x^2}}$

Step-by-step explanation:

$(e^x)'=e^x\\\\\bigg[f\bigg(g(x)\bigg)\bigg]'=f'\bigg(g(x)\bigg)\cdot g'(x)\\\\\left(\dfrac{1}{x}\right)'=-\dfrac{1}{x^2}\\\\====================$

$f(x)=e^\frac{1}{x}=\left(e^\frac{1}{x}\right)'\cdot\left(\dfrac{1}{x}\right)'=e^\frac{1}{x}\cdot\left(-\dfrac{1}{x^2}\right)=-\dfrac{e^\frac{1}{x}}{x^2}$

6 0

4 years ago