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Ganezh [65]
3 years ago
13

One zero of f(x)=x^3-2x^2-5x+6 is 2 what are the zeros of the function

Mathematics
1 answer:
cupoosta [38]3 years ago
7 0

Answer:

Answer:

x=-2, x=1, x=3

Step-by-step explanation:

Step-by-step explanation:

one zero of f(x)=x^3-2x^2-5x+6 is 2 what are the zeros of the function

the following polynomials have the function  

f(x)=x^3-2x^2-5x+6

note 2 is not a zero of the function

but x=-2

to find the other zeros we say  

f(x)/x+2=x^3-2x^2-5x+6/(x+2)

we have the quadratic equation  

x^2-4x+3

factorizing the above, using factorization method

(x^2-3x-x+3)

(x^2-3x)(-x+3)

x(x-3)-1(x-3)

(x-1)(x-3)

x=1, x=3

the zeros of the function are  

x=-2, x=1,x=3

substituting the values back into the function

we have zero

f(1)=1^3-2(1)^2-5(1)+6

F(1)=0

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cupoosta [38]

Answer: The vertex is ( -2, -36)

Step-by-step explanation:

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3 years ago
Write the equation of a circle in standard form with center ( -2,4) and radius 6. Show your work.
grigory [225]

Answer:

( x + 2 )² + ( y - 4 )² = 36

Step-by-step explanation:

Standard equation of a circle - ( x - h )² + ( y - k )² = r²

where r = radius and center is at ( h , k )

The given center is ( -2 , 4 )

Thus h = -2 and k = 4

and the given radius is 6

Thus, r = 6

that being said, we plug in the given values into the standard equation

( x - ( - 2 )² + ( y - 4 )² = 6²

Finally we simplify

In - ( -2 ) the two negative signs cancel out and it turns into + 2

6² = 36

The final equation of the circle is ( x + 2 )² + ( y - 4 )² = 36

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Read 2 more answers
The points , (−15,1) and , (−7,r) lie on a line with slope 5/4. Find the missing coordinate r. Click image to enlarge
Nadya [2.5K]

The missing coordinate r is 11.

Solution:

Given points are (–15, 1) and (–7, r).

x_{1}=-15, x_{2}=-7, y_{1}=1 \text { and } y_{2}=7

Slope (m) = \frac{5}{4}

<u>To find the missing coordinate r:</u>

Slope formula:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substitute the given values in the formula.

$\frac{5}{4}=\frac{r-1}{-7-(-15)}

$\frac{5}{4}=\frac{r-1}{-7+15}

$\frac{5}{4}=\frac{r-1}{8}

Do cross multiplication.

8 \times 5=4(r-1)

40 = 4r – 4

Add 4 on both side of the equation.

44 = 4r

Divide by 4 on both side of the equation.

11 = r

⇒ r = 11

Hence the missing coordinate r is 11.

6 0
3 years ago
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