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Rama09 [41]
3 years ago
7

The length of a rectangle is 3 yd more than twice the width, and the area of the rectangle is 54 yd?. Find the dimensions of the

rectangle.
Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
4 0

Answer:

The length of the rectangle is 37 yards, and the width of the rectangle is 17 yards.

Step-by-step explanation:

Given that the length of a rectangle is 3 yards more than twice the width, and the area of the rectangle is 54 yards, the following calculation must be performed to find the dimensions of the rectangle, knowing that the area of a rectangle arises from multiplying its base by its height:

2X + 3 + X = 54

3X + 3 = 54

3X = 54 - 3

X = 51/3

X = 17

(17 x 2) + 3 = 37

Therefore, the length of the rectangle is 37 yards, and the width of the rectangle is 17 yards.

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Answer:

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Step-by-step explanation:

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If the third side of the triangle is its hypotenuse then

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Third side = \sqrt{(1.4)^{2}+(3.1)^{2}}

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If the third side is one of the perpendicular sides of the triangle and 3.1 m is hypotenuse, then

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