x^3-1
Step-by-step explanation:
because a cubic polynomial would have a cubic exponent to make it a cubic polynomial
Answer:
3.35.
Step-by-step explanation:
very simple!
Solution:
Standard Error Formula:
SEx̄ = S / UNDERROOT N
where,
SEx̄ = Standard Error of the Mean
s = Standard Deviation of the Mean
n = Number of Observations of the Sample
SExĚ„ = 51.60/ âš21 = 11.26004314
So, standard error = 11.26004314
The answer would be yes because if you take a negative number say, -10 and take it to the power of 3 (cub(e)(ing)) -10^3 you have to take -10* itself 3 times and when you do that the first time that you do that you get this -10*-10=100 but them you still have to times it by -10 one more time because its a cube((-e)ing) meaning 3 so we take it times -10 once more and we get are end answer of 100*-10=-1000.
So to answer your question yes it is possible in a cubing now if this was a squaring then no because a negaive time a negative is always a positive.
Enjoy!=)