For this question, 0.008 is the answer.
You can assume x is that number
X multiply 10 = 0.08
To get rid of 10, divide 10 by two sides
As a result, x = 0.008
The new parking lot must hold twice as many cars as the previous parking lot. The previous parking lot could hold 56 cars. So this means the new parking lot must hold 2 x 56 = 112 cars
Let y represent the number of cars in each row, and x be the number of total rows in the parking lot. Since the number of cars in each row must be 6 less than the number of rows, we can write the equation as:
y = x - 6 (1)
The product of cars in each row and the number of rows will give the total number of cars. So we can write the equation as:
xy = 112 (2)
Using the above two equations, the civil engineer can find the number of rows he should include in the new parking lot.
Using the value of y from equation 1 to 2, we get:
x(x - 6) = 112 (3)
This equation is only in terms of x, i.e. the number of rows and can be directly solved to find the number of rows that must in new parking lot.
A three letter word that represents division in a word problem is " cut "
Answer:
34.6 units
Step-by-step explanation:
The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.
The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).
Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:
Distance between point A(-6, 2) and point B(2, 6):
Let,
(nearest tenth)
Distance between B(2, 6) and C(7, 1):
Let,
(nearest tenth)
Distance between C(7, 1) and D(3, -5):
Let,
(nearest tenth)
Distance between D(3, -5) and A(-6, 2):
Let,
(nearest tenth)
Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units
Answer:
18
Step-by-step explanation:
f(x) = 2(1/3)^x
[x = -2]
f(-2) = 2(1/3)⁻²
= 2(9)
= 18
