The sum of two consecutive even integers is at most seven more than half the sum of the next two consecutive even integers
two consecutive even integers: n, n+2
next two consecutive even integers n+4, n+6
n+(n+2) >= 7+1/2(n+4 +n+6)
combine like terms
2n+2 >= 7 +1/2(2n+10)
distribute 1/2
2n+2 >= 7+n+5
2n+2>= n+12
subtract n from each side
n+2>= 12
subtract 2 from each side
n>10
4 integers : 10, 12 ,14, 16
Answer:
Step-by-step explanation:
Do you have a picture to go with this?
I think you forgot to include that T is the midpoint of SV, but what this would mean is that ST = TV.
5x + 2 = 3x + 12
Subtract 2 from both sides.
5x = 3x + 10
Subtract 3x from both sides.
2x = 10
Divide both sides by 2.
x = 5
Now plug that x into ST.
ST = 5(5) + 2
ST = 25 + 2
ST = 27
Answer:
Step-by-step explanation:Here'ly/3fcEdSxs li
nk to the answer:
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