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LuckyWell [14K]
3 years ago
7

I WILL MARK YOU BRAINLYEST if you answer all of my problems !!!!!!!!!!! please need help ASAP

Mathematics
2 answers:
MakcuM [25]3 years ago
8 0
19.- 20dollars/year
20.-the date is a linear function because it has a constant rate of change
21.-2x+4y=48
22.-x=24
23.-y=12
25.- the x intercept indicates the amount of hotdogs that you can buy when you do not buy any hamburgers
26.- the y intercept indicates the amount of burgers you can buy when x=0
horrorfan [7]3 years ago
5 0
19- The rate of change is $20 dollars per year
20- It DOES represent a linear equation because the rate of change is constant

All now pertains to hamburgers and hotdogs:
21- 2x + 4y = 48
22- x-intercept is 24
23- y-intercept is 12
24- Grqph is either below or above in ,y’a answer
25- the x-intercept is how many hotdogs you could get without buying any hamburgers. 24 hotdogs only
26- the y-intercept is how many hamburgers you could buy without getting any hotdogs. Just 12 hamburgers

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Simplify the expression \[\frac{6}{\sqrt{36} + \sqrt{27}} + \frac{6}{\sqrt{27} + \sqrt{18}} + \frac{6}{\sqrt{18} + \sqrt{9}}.\]
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Answer:

= 18 ( 3 + 2(\sqrt{3}  + \sqrt{2} ))

Step-by-step explanation:

6(\sqrt{36} +\sqrt{27}) + 6(\sqrt{27} +\sqrt{18}) + 6(\sqrt{18} + \sqrt{9} )\\= 6( {6} +\sqrt{9*3}) + 6( \sqrt{9*3}  +\sqrt{9*2}) + 6(\sqrt{9*2} + 3 )\\= 6( {6} +3\sqrt{3}) + 6(3\sqrt{3} +3\sqrt{2}) + 6(3\sqrt{2} + 3 )\\=36 + 18\sqrt{3} + 18\sqrt{3} + 18\sqrt{2}+ 18\sqrt{2} + 18\\= 36+18  +18( \sqrt{3}+ \sqrt{3} +\sqrt{2} + \sqrt{2})\\= 54 + 18 (2\sqrt{3} +2\sqrt{2})\\=54 + 36\sqrt{3}  + 36\sqrt{2}\\= 18 ( 3 + 2(\sqrt{3}  + \sqrt{2} ))

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3 years ago
Solve: 7+42*3^(2-3a)=14*3^-2a+7<br> A=-3<br> a=0<br> a=3<br> a=no solution
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Step-by-step explanation:

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4 years ago
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A recent survey showed that in a sample of 100 elementary school teachers, 15 were single. In a sample of 180 high school teache
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Answer:

By using hypothesis test at α = 0.01, we cannot conclude that the proportion of high school teachers who were single greater than the proportion of elementary teachers who were single

Step-by-step explanation:

let p1  be the proportion of elementary teachers who were single

let p2 be the proportion of high school teachers who were single

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H_{0}: p2=p1

H_{a}: p2>p1

We need to calculate the test statistic of the sample proportion for elementary teachers who were single.

It can be calculated as follows:

\frac{p(s)-p}{\sqrt{\frac{p*(1-p)}{N} } } where

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Using the numbers, we get

\frac{0.2-0.15}{\sqrt{\frac{0.15*0.85}{180} } } ≈ 1.88

Using z-table, corresponding  P-Value is ≈0.03

Since 0.03>0.01 we fail to reject the null hypothesis. (The result is not significant at α = 0.01)

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