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3 years ago

Please answer correctly !!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!

Mathematics

1 answer:

tia_tia [17]3 years ago

7 0

Answer:

x = 8

Step-by-step explanation:

well using the theorem we have

$\frac{6}{9}=\frac{x}{12}\\\\\frac{2}{3}=\frac{x}{12}\\\\12[\frac{2}{3}]=12[\frac{x}{12}]\\\\4\cdot 2=x\\\\x=8$

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The number 312 lies between the perfect cubes

dusya [7]

Answer:

The number 312 lies between the perfect cubes 216 and 343.

So the cube root of 312 lies between the number 6 and 7.

This means that the cube root of 312 is an irrational number because it is not a perfect cube root.

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Catherine is a sixth grader at her school. The sixth graders are collecting food items to donate to the local shelter. Their goa

Goryan [66]

Answer:A= 7

Step-by-step explanation:

y=mx+b

512=114x+134

subtract 134 from both sides of the equation,

378=114x

Divide 144 from both sides of the equation to get x by itself

x=6.25

you'll round up because you can't really have a quarter day.

A= 7

3 0

3 years ago

The volume of a shampoo filled into a container is uniformly distributed between 370 and 385 milliliters. (a) What are the mean

Olenka [21]

Answer:

(a) mean = 377.5ml. standard deviation = 4.33

(b) 0.333

Step-by-step explanation:

(a)The mean:

$\mu = \frac{385 + 370}{2} = 377.5 ml$

The standard deviation:

$\sigma = \frac{385 - 370}{\sqrt{12}} = 4.33$

(b)

$P(x < 375) = \frac{375 - 370}{385 - 370} = \frac{1}{3} \approx 0.333$

(c)P(x > m) = 0.95

$\frac{m - 370}{385 - 370} = 0.95$

$m - 370 = 14.25$

$m = 384.25ml$

So the volumn of shampoo should be 384.25ml to exceed 95% of containers.

7 0

3 years ago

In which equation is y a linear function of x?

SVEN [57.7K]

A. y = 4x - 8
This equation is the only equation out of these that make a linear graph.

6 0

2 years ago

2x + y - z = -8

Andreyy89

Answer:

Multiply row 1 by $\frac{1}{2}$ .

Step-by-step explanation:

The augmented matrix of the system of linear equation is described below:

$\left[\begin{array}{cccc}2&1&-1&-8\\0&2&3&-6\\-\frac{1}{2} &1&1&-4\end{array}\right]$

Where $a_{11} = 2$ , if we need to create $a_{11} = 1$ , we need to multiply row 1 by $\frac{1}{2}$ , that is to say:

$\left[\begin{array}{cccc}1&\frac{1}{2} &-\frac{1}{2} &-4\\0&2&3&-6\\-\frac{1}{2} &1&1&-4\end{array}\right]$

Hence, the correct answer is: Multiply row 1 by $\frac{1}{2}$ .

5 0

2 years ago