Question

What is the surface area of the triangular prism shown?

Answer 1

The surface area of the prism is the sum of surface areas of 3 rectangles and 2 triangles.

The surface area of rectangles are

$10*5=50\;cm^2,10*5=50\;cm^2,10*6=60\;cm^2$.

The sum is

$50\;cm^2+50\;cm^2+60\;cm^2 =160\;cm^2$.

The are of each triangle is $\frac{1}{2} 6*4\;cm^2$.

The sum of areas of 2 triangles is $2*\frac{1}{2} 6*4\;cm^2 =24\;cm^2$.

The surface area of the prism is

$160\;cm^2+24\;cm^2=184\;cm^2$.

Answer 2

The surface area is 184 square centimeters