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2 years ago

WILL MARK BRAINLIST!!!!!!!!!!!!!

Mathematics

1 answer:

Llana [10]2 years ago

7 0

Answer:

f(-3) = 6

Step-by-step explanation:

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Please show me the steps and not just the answer 8 - 15 + 20

Lapatulllka [165]

Answer:

Step-by-step explanation:

8-15= -7

-7 + 20 = 13

8 0

2 years ago

Find the slope and the y-intercept for the line. y=2/5x

kondor19780726 [428]

Answer:

Slope= 2/5

y intercept = 0

3 0

3 years ago

Evaluate the six trigonometric functions of the angle 0.

Arturiano [62]

Given:

Right triangle

To find:

The six trigonometric functions of θ

Solution:

Hypotenuse = 18

Adjacent side to θ = 10

Opposite side to θ = ?

Using Pythagoras theorem:

$\text {Hypotenuse}^2 = \text{adjacent}^2+\text{opposite}^2$

$18^2 =10^2+\text{opposite}^2$

$324=100+\text{opposite}^2$

Subtract 100 from both sides.

$224=\text{opposite}^2$

Taking square root on both sides.

$4\sqrt{14}=\text{opposite}$

Using trigonometric ratio formula:

$$\sin\theta =\frac{\text{opposite }}{\text{hypotenuse}}$

$$\sin\theta =\frac{4\sqrt{14} }{18}$

$$\csc\theta =\frac{\text{hypotenuse}}{\text{opposite }}$

$$\csc\theta =\frac{18}{4\sqrt{14} }$

$$\cos \theta=\frac{\text { adjacent side }}{\text { hypotenuse }}$

$$\cos \theta=\frac{10}{18}$

$$\sec \theta=\frac{\text { hypotenuse }}{\text { adjacent side }}$

$$\sec \theta=\frac{18 }{10}$

$$\tan \theta=\frac{\text { opposite side }}{\text { adjacent side }}$

$$\tan \theta=\frac{4\sqrt{14} }{10}$

$$\cot \theta=\frac{\text { adjacent side }}{\text { opposite side }}$

$$\cot \theta=\frac{10}{4\sqrt{14} }$

8 0

3 years ago

Can somebody help me

wel

Answer:

I believe the second one is d

5 0

3 years ago

Write the standard form of the line that passes through the point (1,5) and is parallel to the x -axis. Include your work in you

scoray [572]

Answer:

y = 5

Step-by-step explanation:

A line parallel to the x- axis has equation

y = c

Where c is the value of the y- coordinates the line passes through

The line passes through (1, 5) with y- coordinate of 5, thus

y = 5 ← equation of line

7 0

3 years ago