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Serhud [2]
3 years ago
5

What is the graph of the function f(x) = 1/3x^2

Mathematics
1 answer:
docker41 [41]3 years ago
7 0

Answer: See the figure attached.


Step-by-step explanation:

1. The function shown is of a parabolic equation whose coefficient is positive. This means that the graph will have the shape of a concave parabola.

2. To verify it we can introduce values ​​to the function. Then, you have:

x        y

0       0

1        1/3

-1       1/3

2       4/3

-2      4/3

We can see that the function shown in the graph does not match that of the equation \frac{1}{3}x^2

The graph of this function is shown in the figure attached.

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100 POINTS PLEAS please help
Kamila [148]

Answer:

\textsf{A)} \quad 5u^3-2u^2+5u+8

Step-by-step explanation:

Given expression:

(-2u^3+5u-1)+(7u^3-2u^2+9)

Remove parentheses:

\implies -2u^3+5u-1+7u^3-2u^2+9

Collect like terms:

\implies -2u^3+7u^3-2u^2+5u-1+9

Combine like terms:

\implies 5u^3-2u^2+5u+8

6 0
2 years ago
Read 2 more answers
Can someone help me please I would appreciate it.
Dmitry_Shevchenko [17]
The answer is c to my calculations.
4 0
3 years ago
Describe two to evaluate 37% of the sum of 27 and 3/5 and 15.9
zhuklara [117]
First way is to first find the sum and then find 37% of it. Second way is another way round, find 37 of 27 3/5 and 37% of 15.9 and then add it.

Lets do it
37%=0.37
- its the result
Second way its
0.37* 27 3/5 + 0.37*15.9=10.212 + 5.888=16.095
7 0
3 years ago
Graph ƒ(x) = 2x - 3.
Naya [18.7K]
Ok so your gonna go on the graph and your gonna go to -3 and make a dot then from that point you go up two times and over to the right once and that's your slope
5 0
3 years ago
We looking for distance
drek231 [11]

Answer:

240 m

Step-by-step explanation:

Figure is attached.

The distance the particle travels is the area under the v-t graph over the time interval from 0 min to 4 min.  The reason you can't just multiply velocity by time is that the velocity is changing at a constant rate over the given time interval (the line is going upward--the particls is speeding up).

What's the area under the graph?

The red outline forms a trapezoid.  The area of a trapezoid is  A=\frac{1}{2}h(b_1+b_2)  where the <em>b</em>'s are the lengths of the two parallel base and  <em>h</em>  is the height (the distance between the bases).

Reading the graph carefully (notice the scales!)...

A=\frac{1}{2}(4)(30+90)=(2)(120)=240 \text{m}

8 0
2 years ago
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