Answer:
okay, Its Big brain time.
BB RR BR
Cup1 Cup2 Cup3
2BP 2RP 1BP
2RP
All the cups are in there correct spot and the labels are fine also.
(then someone had to come in dis room with BLUE CAPS AND REPLACE ALL OTHER THE CORRECTLY ORDERER PEN CAPS WITH BLUE PEN CAPS AND SWITCH THE GOSH DARN LABELS. THANKS ALOT, TIM) anyways... i say that the minimum numbers of pens you can test is about 4. probably....
Step-by-step explanation:
Answer:
a. 0.443
b. 0.023
Step-by-step explanation:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
The weight of turkeys is normally distributed with a mean of 22 pounds and a standard deviation of 5 pounds.
This means that 
a. Find the probability that a randomly selected turkey weighs between 20 and 26 pounds.
This is the pvalue of Z when X = 26 subtracted by the pvalue of Z when X = 20. So
X = 26



has a pvalue of 0.788
X = 20



has a pvalue of 0.345
0.788 - 0.345 = 0.443
The answer is 0.443
b. Find the probability that a randomly selected turkey weighs below 12 pounds.
This is the pvalue of Z when X = 12. So



has a pvalue of 0.023
The answer is 0.023.
Answer:
1080
Step-by-step explanation:
Answer: 
Step-by-step explanation:
We can place a rook in each row in
ways.
We can place a rook in each column in
ways.
So the total ways in which we can place a rook in a row or column is 
Now there are 8 ways to choose the column for the first row, 7 ways to choose the column for the second row, and so on. So there are 8! ways to choose a column for a row.
So, we get the final answer by subtracting the 8! from the total ways a rook can be placed which is
when binomial coefficients are not evaluated