All categories

3 years ago

What is 11m - 12 + 1 + 12m

Mathematics

2 answers:

Anit [1.1K]3 years ago

8 0

14m simple math equation

kenny6666 [7]3 years ago

7 0

14m is the answer. Simple math

You might be interested in

Which of the following statements have the same result? Explain each step in solving each one.

Alecsey [184]

Answer:

Non of the above

$f(x) = 4x - 1 \\ f(1) = 4 - 1 \\ f(1) = 3$

$f(x) = 3x - \frac{1}{4} \\ {f}^{ - 1} (x) = \frac{1}{3x} + \frac{1}{12} \\ {f}^{ - 1} (2) = \frac{1}{6} + \frac{1}{12} \\ {f}^{ - 1} (2) = \frac{1}{4}$

III

$2y + 8 = 4y - 2 \\ - 2y = - 10 \\ y = 5$

7 0

3 years ago

What are the values of a1 and r of the geometric series?

igor_vitrenko [27]

A1 or just a as it is in the equations is just the initial term of the sequence. In this case a1=1

r is the common ratio which is that constant ratio found by dividing any term by the term preceding it...

In this case r=3/1=9/3=27/9=etc=3

So a1=1 and r=3, C. is your answer.

5 0

3 years ago

Read 2 more answers

Write two ratios that are equivalent to 3:11

maks197457 [2]

6:22, 9:33, are both equivalent to 3:11.

7 0

3 years ago

Read 2 more answers

alex has twice as much money as jennifer. jennifer has $6 less than shannon. Together they have 54$. How much money does each ha

aleksley [76]

54-6 = 48

48/4 (Alex-twice, Jennifer, Shannon)
48/4= 12

Alex- 12 x 2 = $24

Jennifer- 12 = $12

Shannon- 12+6 (the 6 I subtracted 54-6) = $18

3 0

3 years ago

7. Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

morpeh [17]

Hey there!

Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

Answer :

x = -4 or x = 2 ✅

Explanation :

Quadratic formula : ax² + bx + c = 0 where a ≠ 0

The number of real-number solutions (roots) is determined by the discriminant (b² - 4ac) :

If b² - 4ac > 0 , There are 2 real-number solutions

If b² - 4ac = 0 , There is 1 real-number solution.

If b² - 4ac < 0 , There is no real-number solution.

The roots of the equation are determined by the following calculation:

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}$

Here, we have :

a = 1
b = 2
c = -8

1) Calculate the discriminant :

b² - 4ac ⇔ 2² - 4(1)(-8) ⇔ 4 - (-32) ⇔ 36

b² - 4ac = 36 > 0 ; The equation admits two real-number solutions

2) Calculate the roots of the equation:

▪️ (1)

$x_1 = \frac{ - b - \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ x_1 = \frac{ - 2 - \sqrt{36} }{2(1) } \\ \\ x_1 = \frac{ - 2 - 6}{2} \\ \\ x_1 = \frac{ - 8}{2} \\ \\ \blue{\boxed{\red{x_1 = -4}}}$

▪️ (2)

$x_2 = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ x_2 = \frac{ - 2 + \sqrt{36} }{2(1)} \\ \\ x_2 = \frac{ - 2 + 6}{2} \\ \\ x_2 = \frac{4}{2} \\ \\ \red{\boxed{\blue{x_2 = 2}}}$

>> Therefore, your answers are x = -4 or x = 2.

Learn more about quadratic equations:

brainly.com/question/27638369

6 0

2 years ago

Read 2 more answers