In this problem, you apply principles in trigonometry. Since it is not mentioned, you will not assume that the triangle is a special triangle such as the right triangle. Hence, you cannot use Pythagorean formulas. The only equations you can use is the Law of Sines and Law of Cosines.
For finding side a, you can answer this easily by the Law of Cosines. The equation is
a2=b2 +c2 -2bccosA
a2 = 11^2 + 8^2 -2(11)(8)(cos54)
a2 = 81.55
a = √81.55
a = 9
Then, we use the Law of Sines to find angles B and C. The formula would be
a/sinA = b/sinB = c/sinC
9/sin54° = 11/sinB
B = 80.4°
9/sin54° = 8/sinC
C = 45.6°
The answer would be: a ≈ 9, C ≈ 45.6, B ≈ 80.4
Answer:
50%
Step-by-step explanation:
Answer:
its 23.76
Step-by-step explanation:
I answered in the comments, but now I answered legit (there was a virus earlier lol)
Answer:
A and E would be your answer
Step-by-step explanation:
Answer:
--- quadratic function
--- linear function
--- square root function
Step-by-step explanation:
Given
The attached graph
Required
The domain of each function
Starting from the left; the first function is the quadratic function.
The curve of the quadratic function stops at -2 So, the domain is:
The straight line that starts at -2 and ends at 6 is a linear function.
So, the domain is:
Lastly, the square root function begins at 6. So, the domain is:
