Answer:
Tommy had 56 cents in start and Loren had 7 cents in start.
Step-by-step explanation:
Let,
x be the money Tommy have.
y be the money Loren have.
According to given statement;
Tommy had 8 times more money than Loren.
x = 8y Eqn 1
Parents gave 35 cents to Loren and Tommy spent 14 cents, therefore
x-14=y+35 Eqn 2
Putting x=8y in Eqn 2

Dividing both sides by 7

Putting y=7 in Eqn 1

Hence,
Tommy had 56 cents in start and Loren had 7 cents in start.
Answer:
x^13
2n^2x-5n^7
-6x^10-x
60s^7
6v^7
p^6
-4b^9/3
pls mark as brainliest if its right :)
240 is the answer
Step-by-step explanation:
3x4=12
12x20=240
The answer is 12. This seems like a calculator job
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