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3 years ago

Is 4/7 bigger or smaller than 3/5

Mathematics

2 answers:

crimeas [40]3 years ago

4 0

4/7=.57

3/5=.6

.6 is bigger than .57 so 4/7 is smaller than 3/5

blondinia [14]3 years ago

3 0

$\frac{4}{7}=\frac{4 \times 5}{7 \times 5}=\frac{20}{35} \\
\frac{3}{5}=\frac{3 \times 7}{5 \times 7}=\frac{21}{35} \\ \\
\frac{20}{35} < \frac{21}{35} \\ 
\Downarrow \\
\frac{4}{7} < \frac{3}{5}$

4/7 is smaller than 3/5.

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aalyn [17]

Its A, and both by a factor 1/15

4 0

3 years ago

Read 2 more answers

The answer to all 11.

madam [21]

Answer:

The rate of the current is 2 miles per hour.

Step-by-step explanation:

Let us assume that the rate of the river is v miles per hour.

The speed of the boat is 12 miles per hour.

Let us assume also that the boat can go 21 miles in t hours in the downstream and 15 miles upstream at the same time i.e. t hours.

So, from the condition given we can write that

$12 + v = \frac{21}{t}$ ......... (1), and

$12-v =\frac{15}{t}$ ......... (2)

Now, adding those two equations we get

$24 = \frac{21}{t} +\frac{15}{t} = \frac{36}{t}$

⇒ $t = \frac{3}{2}$ hours

Now, from equation (1), we get,

$12 + v = \frac{21}{\frac{3}{2} } =14$

⇒ v = 2 miles per hour

Therefore, the rate of the current is 2 miles per hour. (Answer)

8 0

3 years ago

Which function is being graphed below?

Keith_Richards [23]

The absolute function will be f(x) = | x - 5 | - 4.

<h3 /><h3>What is an absolute function?</h3>

The absolute function is also known as the mode function. The value of the absolute function is always positive.

The absolute function is given as

f(x) = | x - h | + k

Where h,k is the vertex of the absolute function.

f(x) = | x - 5 | - 4

Therefore the absolute function will be f(x) = | x - 5 | - 4.

More about the absolute function link is given below.

brainly.com/question/10664936

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2 years ago

M-15=9 inverse operation

zheka24 [161]

Answer: 24

Step-by-step explanation:

m - 15 + 15 = 9 + 15

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6 0

3 years ago

Let v = (v1, v2) be a vector in R2. Show that (v2, −v1) is orthogonal to v, and use this fact to find two unit vectors orthogona

andrey2020 [161]

Answer:

a. v.v' = v₁v₂ - v₁v₂ = 0 b. (20, -21)/29 and (-20,21)/29

Step-by-step explanation:

a. For two vectors a, b to be orthogonal, their dot product is zero. That is a.b = 0.

Given v = (v₁, v₂) = v₁i + v₂j and v' = (v₂, -v₁) = v₂i - v₁j, we need to show that v.v' = 0

So, v.v' = (v₁i + v₂j).(v₂i - v₁j)

= v₁i.v₂i + v₁i.(- v₁j) + v₂j.v₂i + v₂j.(- v₁j)

= v₁v₂i.i - v₁v₁i.j + v₂v₂j.i - v₂v₁j.j

i.i = 1, i.j = 0, j.i = 0 and j.j = 1

So, v.v' = v₁v₂i.i - v₁v₁i.j + v₂v₂j.i - v₂v₁j.j

= v₁v₂ × 1 - v₁v₁ × 0 + v₂v₂ × 0 - v₂v₁ × 1

= v₁v₂ - v₂v₁

= v₁v₂ - v₁v₂ = 0

So, v.v' = 0

b. Now a vector orthogonal to the vector v = (21,20) is v' = (20,-21).

So the first unit vector is thus a = v'/║v'║ = (20, -21)/√[20² + (-21)²] = (20, -21)/√[400 + 441] = (20, -21)/√841 = (20, -21)/29.

A unit vector perpendicular to a and parallel to v is b = (-21, -20)/29. Another unit vector perpendicular to b, parallel to a and perpendicular to v is thus a' = (-20,-(-21))/29 = (-20,21)/29

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3 years ago