Answer:
point slope form is y=mx+b
the equation of the line that goes through (6,4) and (7,2) is y=-2x+16
Answer:
The area of a rhombus is
square units.
Step-by-step explanation:
Side length of rhombus = 6 units.
Interior angle of rhombus = 120°
another Interior angle of rhombus = 180°-120° = 60°.
Draw an altitude.
In a right angled triangle
![\sin \theta=\frac{opposite}{hypotenuse}](https://tex.z-dn.net/?f=%5Csin%20%5Ctheta%3D%5Cfrac%7Bopposite%7D%7Bhypotenuse%7D)
![\sin (60)=\frac{h}{6}](https://tex.z-dn.net/?f=%5Csin%20%2860%29%3D%5Cfrac%7Bh%7D%7B6%7D)
![\frac{\sqrt{3}}{2}=\frac{h}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D%3D%5Cfrac%7Bh%7D%7B6%7D)
Multiply both sides by 6.
![3\sqrt{3}=h](https://tex.z-dn.net/?f=3%5Csqrt%7B3%7D%3Dh)
The height of the rhombus is
.
Area of a rhombus is
![Area=base\times height](https://tex.z-dn.net/?f=Area%3Dbase%5Ctimes%20height)
![Area=6\times 3\sqrt{3}](https://tex.z-dn.net/?f=Area%3D6%5Ctimes%203%5Csqrt%7B3%7D)
![Area=18\sqrt{3}](https://tex.z-dn.net/?f=Area%3D18%5Csqrt%7B3%7D)
Therefore, the area of a rhombus is
square units.
The answer is "quadrant II" because first u go five left because of the negative five which is on the x axis then go up 10 because of the positive 10 which on the y axis
I think it's 1/4 because -4/1