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Step2247 [10]
3 years ago
8

How do you list all of the rational zeros of g(x)=x^4-3x^3-53x^2-9x?

Mathematics
1 answer:
coldgirl [10]3 years ago
8 0

Answer:

No lo   se

Step-by-step explanation:

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sure

Step-by-step explanation:

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Brooks used 2/3 of a can of paint to paint the bird feeder. A full can of paint contains 7/8 of a gallon. How much paint did Bro
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3 years ago
Is (1, 3) a solution to the system of equations listed below? (1 point) y= 6x -3 y = x - 2
ololo11 [35]

Answer:

The solution for given system of equation is: x=\frac{1}{5}\:and\:y=\frac{-9}{5} and ordered pair is: \mathbf{(\frac{1}{5},\frac{-9}{5})}

So, (1,3) is not solution to the given system of equations.

Step-by-step explanation:

we can solve the system of equations to find the value of x and y and then verify if (1,3) is a solution or not.

The system of equation given is:

y=6x-3\\y=x-2

Solving:

Let:

y=6x-3--eq(1)\\y=x-2--eq(2)

Put value of y from equation 2 into equation 1

y=6x-3\\Put\:y=x-2\\x-2=6x-3\\x-6x=-3+2\\-5x=-1\\x=\frac{-1}{-5}\\x=\frac{1}{5}

Now, put value of x in equation 2 to find value of y

y=x-2\\Put\:x=\frac{1}{5} \\y=\frac{1}{5} -2\\y=\frac{1-2*5}{5} \\y=\frac{1-10}{5}\\ y=\frac{-9}{5}

So, the solution for given system of equation is: x=\frac{1}{5}\:and\:y=\frac{-9}{5} and ordered pair is: \mathbf{(\frac{1}{5},\frac{-9}{5})}

So, (1,3) is not solution to the given system of equations.

7 0
2 years ago
What is six times six?​
Alona [7]

Answer:

36

Step-by-step explanation:

6•6=36

5 0
3 years ago
Read 2 more answers
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