HELP PLEASE

What is the slope between (0,-2) and (1,1)

Yanka [14]

You need to give us a picture of the slope

3 0

3 years ago

Read 2 more answers

Complete all 3 questions.

nalin [4]

Answer:

1.x^2-5x

2.2x^2+15x+18

3. x^2+20x+18

Step-by-step explanation:

1. x(x-5) x*x-5*x = x^2-5x

2. (x+6)(2x+3) x*2x+x*3+6*2x+6*3= 2x^2+15x+18

3.(2x^2+15x+18)-(x^2-5x)=x^2+20x+18

3 0

3 years ago

In parallelogram ABCD , diagonals AC¯¯¯¯¯ and BD¯¯¯¯¯ intersect at point E, AE = 3x - 5, and CE = x + 11.

german

Answer:

38

Step-by-step explanation:

For the case of a parallelogram, when the diagonals ( in our case AC & BD) are intersected, they are basically bisected ( divided into two equal halves ). Therefore when the diagonals intersect at point E, we can say that the diagonal AC is divided in two equal halves which in our case are AE and CE. since AE and CE are equal , we can say that,

$AE= CE \\or\\3x-5 = x+11 ---- (1)\\now solving (1) for x, \\3x-x=11+5\\2x=16\\x=8-----> (2)\\\\as \\ AC = AE+CE\\AC = 3x-5+x+11\\AC = 4x+6\\\\\\from (2)\\\\\\AC= 4(8)+6\\AC = 32+6\\AC = 38\\\\since AC = BD ( Diagonals are of same Length )\\therefore \\BD =38$

5 0

4 years ago

a band of 45 ewoks crash-landed in the forest last night. this sounds like a small problem, but the population will grow at the

kogti [31]

Given Information:

Starting population = P₀ = 45

rate of growth = 22%

Required Information:

Population every five years from this year to the year 2050 = ?

Answer:

$Year \: 2020 = P(0) = 45e^{0} = 45\\\\Year \: 2025 = P(5) = 45e^{0.22*5} = 135\\\\Year \: 2030 = P(10) = 45e^{0.22*10} = 406\\\\Year \: 2035 = P(15) = 45e^{0.22*15} = 1,220\\\\Year \: 2040 = P(20) = 45e^{0.22*20} = 3,665\\\\Year \: 2045 = P(25) = 45e^{0.22*25} = 11,011\\\\Year \: 2050 = P(30) = 45e^{0.22*30} = 33,079\\\\$

Step-by-step explanation:

The population growth can be modeled as an exponential function,

$P(t) = P_0e^{rt}$

Where P₀ is the starting population, r is the rate of growth of the population and t is the time in years.

We are given that starting population of 45 and growth rate of 22%

$P(t) = 45e^{0.22t}$

Assuming that the starting year is 2020,

$Year \: 2020 = P(0) = 45e^{0} = 45\\\\Year \: 2025 = P(5) = 45e^{0.22*5} = 135\\\\Year \: 2030 = P(10) = 45e^{0.22*10} = 406\\\\Year \: 2035 = P(15) = 45e^{0.22*15} = 1,220\\\\Year \: 2040 = P(20) = 45e^{0.22*20} = 3,665\\\\Year \: 2045 = P(25) = 45e^{0.22*25} = 11,011\\\\Year \: 2050 = P(30) = 45e^{0.22*30} = 33,079\\\\$

Therefore, the starting population of ewoks was 45 in 2020 and increased to 33,079 by 2050 in a time span of 30 years.

8 0

3 years ago

the waiting time to ride a roller coaster is 20 minutes when 150 people are in line. how long is the waiting time when 240 peopl

Margaret [11]

We have an equation: 20/?= 150/240

Cross multiply:
150*?= 20*240
⇒ ?= 20*240/150= 32

The final answer is 32 minutes~

6 0

3 years ago