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lilavasa [31]
3 years ago
15

How many solutions does the system of equations have? 6x+y=2 -18x+3y=12

Mathematics
2 answers:
Tamiku [17]3 years ago
6 0
There will be one solution. To solve that:
1. Get the y alone by switching the places.
6x+y=2 > y=2-6x 
-18x+3y=12 > 3y=12-18x > Then divide 3 on each number > y=4-6x
After doing that, you can solve this in graphing or algebra way.

Ima do the algebra way: 

SO we have 2 system of equations. Now pick one equestion.
I will pick, y=2-6x. Now Ima replace the Y with the other equation y=4-6x >  
4-6x=2-6x.

Now solve. And get >  0 aka Infinite Solution.
kenny6666 [7]3 years ago
6 0
See if they are paralell, if they are, there are no solutions
thn see if they are the same line, if they are, there is infinite soutions

so

6x+1y=2
-18x+3y=12
divide 2nd equation by -3
6x-y=4

compare
6x+y=2 and
6x-y=4
they are actually perpenduclar
mean 1 soltuions

if yo wantedsoltion
add

6x+y=2
<u>6x-y=4 +</u>
12x+0y=6
12x=6
x=1/2

6x+y=2
6(1/2)+y=2
3+y=2
y=-1



x=1/2
y=-1
(1/2,-1)
1 soluiton
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Answer:

a) Area of the base of the pyramid = 15.6\ mm^{2}

b) Area of one lateral face = 24\ mm^{2}

c) Lateral Surface Area = 72\ mm^{2}

d) Total Surface Area = 87.6\ mm^{2}

Step-by-step explanation:

We are given the following dimensions of the triangular pyramid:

Side of triangular base = 6mm

Height of triangular base = 5.2mm

Base of lateral face (triangular) = 6mm

Height of lateral face (triangular) = 8mm

a) To find Area of base of pyramid:

We know that it is a triangular pyramid and the base is a equilateral triangle. \text{Area of triangle = } \dfrac{1}{2} \times \text{Base} \times \text{Height} ..... (1)\\

{\Rightarrow \text{Area of pyramid's base = }\dfrac{1}{2} \times 6 \times 5.2\\\Rightarrow 15.6\ mm^{2}

b) To find area of one lateral surface:

Base = 6mm

Height = 8mm

Using equation (1) to find the area:

\Rightarrow \dfrac{1}{2} \times 8 \times 6\\\Rightarrow 24\ mm^{2}

c) To find the lateral surface area:

We know that there are 3 lateral surfaces with equal height and equal base.

Hence, their areas will also be same. So,

\text{Lateral Surface Area = }3 \times \text{ Area of one lateral surface}\\\Rightarrow 3 \times 24 = 72 mm^{2}

d) To find total surface area:

Total Surface area of the given triangular pyramid will be equal to <em>Lateral Surface Area + Area of base</em>

\Rightarrow 72 + 15.6 \\\Rightarrow 87.6\  mm^{2}

Hence,

a) Area of the base of the pyramid = 15.6\ mm^{2}

b) Area of one lateral face = 24\ mm^{2}

c) Lateral Surface Area = 72\ mm^{2}

d) Total Surface Area = 87.6\ mm^{2}

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3 years ago
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JulijaS [17]
Hope this helps again! :)

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Answer:

       

Step-by-step explanation:


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Mnenie [13.5K]
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3 0
2 years ago
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What's the surface area of the square pyramid?? <br><br> Please someone answer fast
Eddi Din [679]

Answer:

33

Step-by-step explanation:

The base/square:

3*3 = 9

The sides:

(3*4)/2 = 6

4 sides:

6*4 = 24

Total:

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8 0
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