How many solutions does the system of equations have? 6x+y=2 -18x+3y=12

2 answers:

6 0

There will be one solution. To solve that:
1. Get the y alone by switching the places.
6x+y=2 > y=2-6x
-18x+3y=12 > 3y=12-18x > Then divide 3 on each number > y=4-6x
After doing that, you can solve this in graphing or algebra way.

Ima do the algebra way:

SO we have 2 system of equations. Now pick one equestion.
I will pick, y=2-6x. Now Ima replace the Y with the other equation y=4-6x >
4-6x=2-6x.

Now solve. And get > 0 aka Infinite Solution.

kenny6666 [7]3 years ago

6 0

See if they are paralell, if they are, there are no solutions
thn see if they are the same line, if they are, there is infinite soutions

so

6x+1y=2
-18x+3y=12
divide 2nd equation by -3
6x-y=4

compare
6x+y=2 and
6x-y=4
they are actually perpenduclar
mean 1 soltuions

if yo wantedsoltion
add

6x+y=2
<u>6x-y=4 +</u>
12x+0y=6
12x=6
x=1/2

6x+y=2
6(1/2)+y=2
3+y=2
y=-1

x=1/2
y=-1
(1/2,-1)
1 soluiton

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Just #35 please piecewise functions

saveliy_v [14]

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If you look at the attached screenshot, you will see that if you keep your friend's function, inputting 3 will result in two outputs of 4 and -3, so therefore, $y=\left \{ {{2x-2,x\leq 3} \atop {-3,x\geq 3}} \right.$ cannot represent a piecewise function.