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mixas84 [53]
3 years ago
11

If male and female college students work an average of 15 hours per week during the school year and the standard deviation is 5.

4 for male students and 2.3 for female students, what may we conclude?
Mathematics
2 answers:
charle [14.2K]3 years ago
5 0

Answer: the male sample is more spread than the female sample

Step-by-step explanation:

The mean is the same for both genres, but the standard deviation form males is bigger than the one for females.

This means that the data of the male students is more spread than the female data (so there are more male students that study more hours, but there also are more male students that study less hours).

So the general conclusion is that the male sample is more spread than the female sample

ki77a [65]3 years ago
3 0
The variance of hours males spend working is almost two times as large as females. 60% of those females are more likely to work between 12.7 to 17.3 hours while 60% of the males work between 9.6 to 20.3 hours based on one standard deviation.
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How would I solve this? Can I get steps?
ratelena [41]

Answer:

<em>p = ± q / 5r + 8; Option D</em>

Step-by-step explanation:

We are given the following equation; q^2 / p^2 - 16p + 64 = 25r^2;

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q^2 / ( p - 8 )^2 = 25r^2 ⇒ multiply either side by ( p - 8 )^2,

q^2 = 25r^2 * ( ( p - 8 )^2 ) ⇒ divide either side by 25r^2,

q^2 / 25r^2 = ( p - 8 )^2 ⇒ Now apply square root on either side,

| p - 8 | = √( q^2 / 25r^2 ) ⇒ Simplify,

| p - 8 | = q / 5r,

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