3(x+4)=5(x-2) I really need help i have no idea how to do it
2 answers:
You might be interested in
Answer:
The Conclusion is
Diagonals AC and BD,
a. Bisect each other
b. Not Congruent
c. Not Perpendicular
Step-by-step explanation:
Given:
[]ABCD is Quadrilateral having Vertices as
A(-1, 1),
B(2, 3),
C(6, 0) and
D(3, -2).
So the Diagonal are AC and BD
To Check
The diagonals AC and BD
a. Bisect each other. B. Are congruent. C. Are perpendicular.
Solution:
For a. Bisect each other
We will use Mid Point Formula,
If The mid point of diagonals AC and BD are Same Then
Diagonal, Bisect each other,
For mid point of AC
Substituting the coordinates of A and C we get
Similarly, For mid point of BD
Substituting the coordinates of B and D we get
Therefore The Mid point of diagonals AC and BD are Same
Hence Diagonals,
a. Bisect each other
B. Are congruent
For Diagonals to be Congruent We use Distance Formula
For Diagonal AC
Substituting A and C we get
Similarly ,For Diagonal BD
Substituting Band D we get
Therefore Diagonals Not Congruent
For C. Are perpendicular.
For Diagonals to be perpendicular we need to have the Product of slopes must be - 1
For Slope we have
Substituting A and C we get
Similarly, for BD we have
The Product of slope is not -1
Hence Diagonals are Not Perpendicular.