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evablogger [386]
3 years ago
13

If the vertices of triangle bcd are b(-3,3), c(3,5), and d(-1,0), what is the perimeter

Mathematics
1 answer:
zloy xaker [14]3 years ago
7 0
Distance formlula
D=\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}

when you want to find the distance between points (x1,y1) and (x2,y2)


we nee
distace from
b to c
c to d
d to b


b to c is (-3,3) to (3,5)
D=\sqrt{(3-(-3))^{2}+(5-3)^{2}}=2√10

c to d is (3,5) to (-1,0)
D=\sqrt{(-1-3)^{2}+(0-5)^{2}}=√41

d to b is (-1,0) to (-3,3)
D=\sqrt{(-3-(-1))^{2}+(3-0)^{2}}=√13

add

b to c+c to d+d to b=2√10+√41+√13

perimiter=2√10+√41+√13 units





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2 years ago
PLS HELP WILL GIVE BRAINLIEST :)
Rus_ich [418]

Step-by-step explanation:

the slope intercept form is

y = ax + b

"a" being the slope, "b" being the y- intercept (which is the y-value when x = 0).

the slope here :

in the table x is always increasing by 2.

and y is always investing by 1.

so, the slope is 1/2

the y-intercept :

we need to find the y-value for x = 0.

but we don't have a data point with x = 0 in the table.

so, we have to extend the structure of the table to the left.

x decreases by 2 (making it 0), and y decreases by 1 (making it -1).

therefore, the y- intercept (b) is -1.

and the line equation is

y = (1/2)x - 1

not sure about "the other method".

there is the point-slope form of the equation :

y - y1 = a(x - x1)

again with "a" begin the slope, and (x1, y1) being a point on the line.

if we get the y-intercept in the table, then this point is (0, y1).

and the equation would be

y - y1 = ax

in our case

y + 1 = (1/2)x

and another method ?

sometimes people write

nx + my = c

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6 0
3 years ago
In Lake Erie, walleye fish are abundant. The lengths of walleyes follow a Normal distribution with a mean of 31 inches and a sta
AlladinOne [14]

Answer:

d. Approximately 84% of walleyes have lengths less than 34.6 inches.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 31

Standard deviation = 3.6

a. Approximately 32% of walleyes have lengths less than 27.4 inches.

27.4 is one standard deviation below the mean.

By the Empirical Rule, 68% of the measures are within 1 standard deviation of the mean. Of the other 32% more than 1 standard deviation from the mean, 16% of the lengths are less than 27.4 and 16% are greather than 31+3.6 = 34.6.

So approximately 16% of walleyes have lengths less than 27.4 inches, which means that this statement is false.

b. Approximately 95% of walleyes have lengths greater than 23.8 inches.

23.8 is two standard deviations below the mean.

By the Empirical Rule, 95% of the measures are within 2 standard deviations of the mean. Of the 5% that is more than 2 standard deviations from the mean, 2.5% is greater than 2 standard deviations above the mean(greater than 38.2, in this problem), and 2.5% is lower than 2 standard deviations below the mean(lower than 23.8 in this problem).

So 2.5% of walleyes have lengths lower than 23.8 and 100-2.5 = 97.5% have lengths greater than 23.8, which means that this statement is false.

c. Approximately 16% of walleyes have lengths longer than 38.2 inches.

38.2 is two standard deviations above the mean.

By the Empirical Rule, 95% of the measures are within 2 standard deviations of the mean. Of the 5% that is more than 2 standard deviations from the mean, 2.5% is greater than 2 standard deviations above the mean(greater than 38.2, in this problem), and 2.5% is lower than 2 standard deviations below the mean(lower than 23.8 in this problem).

So 2.5% of walleyes have lengths longer than 38.2 inches, which means that this statement is false.

d. Approximately 84% of walleyes have lengths less than 34.6 inches.

34.6 is one standard deviation above the mean.

The empirical rule is symmetric, which means that 50% of the measures are above the mean and 50% of the meausures are below the mean.

Also, 68% of the measures are within 1 standard deviation of the mean. Of those, 34% are between one standard deviation below the mean and the mean, and 34% are between the mean and one standard deviation above the mean.

So, 50% below the mean, plus 34% between the mean and 34.6 means that approximately 84% of the walleyes have lengths less than 34.6 inches, which means that this statement is true.

e. Approximately 2.5% of walleyes have lengths between 31 inches and 34.6 inches.

31 is the mean

34.6 is one standard deviation above the mean.

By the Empirical Rule, 68% of the measures are within 1 standard deviation of the mean. Of those, 34% are between one standard deviation below the mean and the mean, and 34% are between the mean and one standard deviation above the mean.

So 34% of walleyes have lengths between 31 inches and 34.6 inches, which means that this statement is false.

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4 years ago
Look at the graph of the functions. Given the original function, f(x)=x to the square root,what is a possible equation for the t
Brums [2.3K]

Answer: C on edg

Step-by-step explanation:

F(x)= √2(x+4)

3 0
3 years ago
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