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evablogger [386]
3 years ago
13

If the vertices of triangle bcd are b(-3,3), c(3,5), and d(-1,0), what is the perimeter

Mathematics
1 answer:
zloy xaker [14]3 years ago
7 0
Distance formlula
D=\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}

when you want to find the distance between points (x1,y1) and (x2,y2)


we nee
distace from
b to c
c to d
d to b


b to c is (-3,3) to (3,5)
D=\sqrt{(3-(-3))^{2}+(5-3)^{2}}=2√10

c to d is (3,5) to (-1,0)
D=\sqrt{(-1-3)^{2}+(0-5)^{2}}=√41

d to b is (-1,0) to (-3,3)
D=\sqrt{(-3-(-1))^{2}+(3-0)^{2}}=√13

add

b to c+c to d+d to b=2√10+√41+√13

perimiter=2√10+√41+√13 units





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Answer:

Step-by-step explanation:

A ' = (-2, -3)

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=======================================================

Explanation:

To apply an x axis reflection, we simply change the sign of the y coordinate from positive to negative, or vice versa. The x coordinate stays as is.

Algebraically, the reflection rule used can be written as

Applying this rule to the three given points will mean....

Point A = (-2, 3) becomes A ' = (-2, -3)

Point B = (0, 3) becomes B ' = (0, -3)

Point C = (-1, -1) becomes C ' = (-1, 1)

The diagram is provided below.

Side note: Any points on the x axis will stay where they are. That isn't the case here, but its for any future problem where it may come up. This only applies to x axis reflections.

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The diagram below shows an example of this for the point (-4,-2) rotating to (-2, 4). The center of the rotation is the origin (0,0).

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