Question

If the vertices of triangle bcd are b(-3,3), c(3,5), and d(-1,0), what is the perimeter

Answer 1

Distance formlula
D=$\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}$

when you want to find the distance between points (x1,y1) and (x2,y2)


we nee
distace from
b to c
c to d
d to b


b to c is (-3,3) to (3,5)
D=$\sqrt{(3-(-3))^{2}+(5-3)^{2}}$=2√10

c to d is (3,5) to (-1,0)
D=$\sqrt{(-1-3)^{2}+(0-5)^{2}}$=√41

d to b is (-1,0) to (-3,3)
D=$\sqrt{(-3-(-1))^{2}+(3-0)^{2}}$=√13

add

b to c+c to d+d to b=2√10+√41+√13

perimiter=2√10+√41+√13 units