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evablogger [386]
3 years ago
13

If the vertices of triangle bcd are b(-3,3), c(3,5), and d(-1,0), what is the perimeter

Mathematics
1 answer:
zloy xaker [14]3 years ago
7 0
Distance formlula
D=\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}

when you want to find the distance between points (x1,y1) and (x2,y2)


we nee
distace from
b to c
c to d
d to b


b to c is (-3,3) to (3,5)
D=\sqrt{(3-(-3))^{2}+(5-3)^{2}}=2√10

c to d is (3,5) to (-1,0)
D=\sqrt{(-1-3)^{2}+(0-5)^{2}}=√41

d to b is (-1,0) to (-3,3)
D=\sqrt{(-3-(-1))^{2}+(3-0)^{2}}=√13

add

b to c+c to d+d to b=2√10+√41+√13

perimiter=2√10+√41+√13 units





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         2 · 1

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