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soldi70 [24.7K]
3 years ago
10

Draw quick pictures and write to explain how to break apart addenda to find the sum of 324+231

Mathematics
1 answer:
vlabodo [156]3 years ago
8 0
What is an addenda??

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An automated egg carton loader has a 1% probability of cracking an egg, and a customer will complain if more than one egg per do
vaieri [72.5K]

Answer:

a) Binomial distribution B(n=12,p=0.01)

b) P=0.007

c) P=0.999924

d) P=0.366

Step-by-step explanation:

a) The distribution of cracked eggs per dozen should be a binomial distribution B(12,0.01), as it can model 12 independent events.

b) To calculate the probability of having a carton of dozen eggs with more than one cracked egg, we will first calculate the probabilities of having zero or one cracked egg.

P(k=0)=\binom{12}{0}p^0(1-p)^{12}=1*1*0.99^{12}=1*0.886=0.886\\\\P(k=1)=\binom{12}{1}p^1(1-p)^{11}=12*0.01*0.99^{11}=12*0.01*0.895=0.107

Then,

P(k>1)=1-(P(k=0)+P(k=1))=1-(0.886+0.107)=1-0.993=0.007

c) In this case, the distribution is B(1200,0.01)

P(k=0)=\binom{1200}{0}p^0(1-p)^{12}=1*1*0.99^{1200}=1* 0.000006 = 0.000006 \\\\ P(k=1)=\binom{1200}{1}p^1(1-p)^{1199}=1200*0.01*0.99^{1199}=1200*0.01* 0.000006 \\\\P(k=1)= 0.00007\\\\\\P(k\leq1)=0.000006+0.000070=0.000076\\\\\\P(k>1)=1-P(k\leq 1)=1-0.000076=0.999924

d) In this case, the distribution is B(100,0.01)

We can calculate this probability as the probability of having 0 cracked eggs in a batch of 100 eggs.

P(k=0)=\binom{100}{0}p^0(1-p)^{100}=0.99^{100}=0.366

5 0
3 years ago
X= 3 is not a solution to 12 + x = 16 Why not?
Inga [223]
Because 12 + 3 is not equal to 16...
4 0
3 years ago
Read 2 more answers
P
statuscvo [17]

Answer:

18ywjhtzk8ywbhuj

Step-by-step explanation:

ujzjtzjdjwjduxhxhwbsusuww

4 0
2 years ago
279 is 33 1/2 of what amount
ycow [4]

Answer:

33% of 279 is equivalent to multiplying them: 33% × 279.

Step-by-step explanation:

4 0
3 years ago
What is the slope of a line that is parallel to the line shown?
Rasek [7]

Answer:

-4/3 the slopes are always the same when lines are parallel

6 0
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