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3 years ago

Integers contain the whole numbers.true or false

Mathematics

2 answers:

KonstantinChe [14]3 years ago

6 0

True , hope this helps :)

julia-pushkina [17]3 years ago

4 0

True, Integers mean "whole", and it cannot be a fraction or decimal

hope this helps

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Given: g(x)=1/x+2 and h(x)=3x Check all restrictions on the domain of gOh.

Vlad [161]

The composite function $(g \circle h)(x)$ works like this:

Take a number $x$ as input
Evaluate h(x) = 3x. Let's call this output z.
Evaluate g(x) = 1/(z+2)

So, if we substitute back z = 3x, the final output is 1/(3x+2). We know that the denominator of a fraction can't be zero, so we must impose

$3x+2 \neq 0 \iff 3x \neq -2 \iff x \neq -\dfrac{2}{3}$

3 0

2 years ago

Read 2 more answers

1. In the figure, m DE = 106 degrees and m BC = 62 degrees. The diagram is not to scale.

k0ka [10]

For question 1, the formula for that is m1= 1/2(a-b). 106 being A and 62 being B. You should get m1=.5*(106-62) which equals B.22

8 0

2 years ago

I need this fast yal. i am willing to give brainly

andreyandreev [35.5K]

Answer:

The answer is

y = 6x + 43

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

To find the equation of the parallel line we must first find the slope of the original line

The original line is y = 6x + 1

Comparing with the general equation above

Slope = 6

Since the lines are parallel their slope are also the same

Slope of parallel line = 6

The equation of the line using point (-7,1) and slope 6 is

We have the final answer as

y = 6x + 43

Step-by-step explanation:

srry if this is wring, its what i got also pls give brainliest, im trying to get to vituoso :3

7 0

2 years ago

The general solution of 2 y ln(x)y' = (y^2 + 4)/x is

Sav [38]

Replace $y'$ with $\dfrac{\mathrm dy}{\mathrm dx}$ to see that this ODE is separable:

$2y\ln x\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y^2+4}x\implies\dfrac{2y}{y^2+4}\,\mathrm dy=\dfrac{\mathrm dx}{x\ln x}$

Integrate both sides; on the left, set $u=y^2+4$ so that $\mathrm du=2y\,\mathrm dy$ ; on the right, set $v=\ln x$ so that $\mathrm dv=\dfrac{\mathrm dx}x$ . Then

$\displaystyle\int\frac{2y}{y^2+4}\,\mathrm dy=\int\dfrac{\mathrm dx}{x\ln x}\iff\int\frac{\mathrm du}u=\int\dfrac{\mathrm dv}v$

$\implies\ln|u|=\ln|v|+C$

$\implies\ln(y^2+4)=\ln|\ln x|+C$

$\implies y^2+4=e^{\ln|\ln x|+C}$

$\implies y^2=C|\ln x|-4$

$\implies y=\pm\sqrt{C|\ln x|-4}$

4 0

2 years ago

Find the length of base ab of trapezoid abcd

vesna_86 [32]

By doing base times area that is what I will do

6 0

3 years ago