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3 years ago

Medium sodas cost $1.25 and hot dogs cost $2.50.

Mathematics

2 answers:

Llana [10]3 years ago

8 0

Answer:

<h2>They can buy 16 sodas.</h2>

Step-by-step explanation:

We know that each soda costs $15. So, if they have $20 to buy sodas, we can find the amount of sodas by applying the rule of three:

So, if one cost $15, how many soda could they but with $20?

$x=$20\frac{1soda}{$1.25} =16(sodas)$

<h3>If we make a table would be like this:</h3>

Amount of Soda Cost ($)

1 1.25

2 2.50

3 3.75

4 5

5 6.25

6 7.50

7 8.75

8 10

9 11.25

10 12.50

11 13.75

12 15

13 16.25

14 17.50

15 18.75

16 20

<h3><em></em></h3><h3><em>Therefore, with $20 they can buy 16 sodas.</em></h3>

Sindrei [870]3 years ago

6 0

She could buy 16 sodas

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Answer:

The work is in the explanation.

Step-by-step explanation:

The sine addition identity is:

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The sine difference identity is:

$\sin(a-b)=\sin(a)\cos(b)-\cos(a)\sin(a)$ .

The cosine addition identity is:

$\cos(a+b)=\cos(a)\cos(b)-\sin(a)\sin(b)$ .

The cosine difference identity is:

$\cos(a-b)=\cos(a)\cos(b)+\sin(a)\sin(b)$ .

We need to find a way to put some or all of these together to get:

$\sin(a)\cos(b)=\frac{\sin(a+b)+\sin(a-b)}{2}$ .

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Let's start there then.

There is a plus sign in between them so let's add those together:

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There are two pairs of like terms. I will gather them together so you can see it more clearly:

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3 years ago

The top and bottom margins of a poster are each 15 cm and the side margins are each 10 cm. If the area of printed material on th

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Answer:

the dimension of the poster = 90 cm length and 60 cm width i.e 90 cm by 60 cm.

Step-by-step explanation:

From the given question.

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Therefore pq = 2400 cm ²

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To find the dimensions of the poster; we have:

the length of the poster to be p+30 and the width to be $\dfrac{2400 \ cm^2}{p} + 20$

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q = 40

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