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Rashid [163]
3 years ago
15

What is 73/9 as a mixed number

Mathematics
2 answers:
yarga [219]3 years ago
8 0
8 1/9 because 9 times 8 is 72 and 73-72=1 so 8 1/9
Sever21 [200]3 years ago
8 0
8\frac{1}{9} is the mixed number of \frac{73}{9}

i hope this helped 
:)
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The coordinates of the vertices of □PQR are (-2,5), Q(-1,), and R(7,3). Determine whether □ PQR is a right triangle. Show Your W
alexdok [17]

Answer:

Slope of PQ

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4 0
3 years ago
PLS HELP ME ASAP FOR 12 and 13!!! (SHOW WORK FOR BOTH!!!) + LOTS KF POINTS!!
pychu [463]

12.
Distribute the negative
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Please mark Brainliest if it helped.


8 0
2 years ago
Find surface area of this regular pyramid
liq [111]

Answer:

189 ft²

Step-by-step explanation:

Here is the formula...

1/2 * 6 * 36 + 81

Hope this helps

7 0
2 years ago
Given: BD bisects ABC. Auxiliary EA is drawn such that AE || BD. Auxiliary BE is an extension of BC
AnnZ [28]
The required proof is given in the table below:

\begin{tabular}{|p{4cm}|p{6cm}|} 
 Statement & Reason \\ [1ex] 
1. $\overline{BD}$ bisects $\angle ABC$ & 1. Given \\
2. \angle DBC\cong\angle ABD & 2. De(finition of angle bisector \\ 
3. $\overline{AE}$||$\overline{BD}$ & 3. Given \\ 
4. \angle AEB\cong\angle DBC & 4. Corresponding angles \\
5. \angle AEB\cong\angle ABD & 5. Transitive property of equality \\ 
6. \angle ABD\cong\angle BAE & 6. Alternate angles
\end{tabular}
\begin{tabular}{|p{4cm}|p{6cm}|}
7. \angle AEB\cong\angle BAE & 7. Transitive property of equality \\
8. \overline{EB}\cong\overline{AB} & 8. From 7. $\Delta ABE$ is isosceles \\
9. EB = AB & 9. De(finition of congruence \\ 10. $\frac{AD}{DC}=\frac{EB}{BC}$ & 10. Triangle proportionality theorem \\
11. $\frac{AD}{DC}=\frac{AB}{BC}$ & 11. Substitution Property of equality \\[1ex] 
\end{tabular}

7 0
3 years ago
Read 2 more answers
Solve the equation:<br><br> a) -3 = 7+2t/3<br><br> b) 4(5x-2) = 7(2x+3) <br><br> c) 2x-6 = 30-2.5x
Umnica [9.8K]
Let's start by solving the first equation.

a) -3 = 7 + 2t/3 
To begin simplifying this equation, we should multiply both sides by 3 to get rid of the denominator on the right side of the equation.
-9 = 7 + 2t
Next, we should subtract 7 from both sides to cancel out the 7 on the right side.
-16 = 2t
Finally, we should divide both sides by 2.
t= -8


Now let's move on to the next equation.

b) 4(5x-2) = 7(2x+3)
Let's use the distributive property to get rid of the parentheses and their coefficients.
20x-8 = 14x + 21

Now, lets subtract 14x from both sides of the equation.

6x - 8 = 21

Next, let's add 8 to both sides of the equation.

6x = 29

And divide both sides by the coefficient of x, which is 6.

x = 29/6 or 4 5/6

Now for the last equation.

C) 2x - 6 = 20 - 2.5x
First, we should add 2.5x to both sides to cancel out the -2.5x on the right side of the equation.
4.5x - 6 = 20
Now, let's add 6 to both sides to get the variable term alone.
4.5x = 26
Finally, we should divide both sides by 4.5 to get x by itself.
x = 5 7/9

Hope this helps! :)
7 0
3 years ago
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