A.) 106.6
B.) 4.56
..........,.,...,,,
Answer:
3.3 × 
Step-by-step explanation:
I hope this helps!
Answer:
what is the question??
Step-by-step explanation:
Answer:
≈0.487
Step-by-step explanation:
I think this is your full question right?
Jose surveyed the length of TV commercials (in seconds). Find, to 3 decimal places, the experimental probability that a randomly chosen TV commercial will last:
Length Frequency
0-19 17
20-39 38
40-59 19 20 to 39 seconds.
60+ 20 to 4
Here is my anwer:
experimental probability = relative frequency =
Total frequencies = 17 + 38 +18 + 4 = 78
P(20 to 39s) = 38/78 ≈0.487
V = L * W * H
V = 1/4 * 2/3 * 3/5
V = (1 * 2 * 3) / (4 * 3 * 5)
V = 6/60 reduces to 1/10 m^3 <==