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Troyanec [42]
3 years ago
12

Solve the inequality |2h-3| >1

Mathematics
1 answer:
mel-nik [20]3 years ago
5 0

Answer:

\large\boxed{h>2\ \vee\ h

Step-by-step explanation:

|2h-3|>1\iff2h-3>1\ \vee\ 2h-34\ \vee\ 2h2\ \vee\ h

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Please help! If possible please show your work. Thank you in advance!! :D
Rudiy27

Answer:

  • (-4)³ = -64
  • -64

Step-by-step explanation:

The first step in solving the equation is to cube both sides:

  (∛x)³ = (-4)³ . . . . . = (-4)(-4)(-4) = 16(-4) = -64

  x = -64 . . . . . simplified

__

We're not sure what "checking" is supposed to involve here. Usually, one would check the answer by seeing if a true statement is made when the answer is put into the original equation.

  ∛(-64) = -4 . . . true

Many calculators will not compute √(-64) because they compute roots using logarithms. The log of a negative number is not defined.

So, the way one would check this is to cube both sides, which is how we got the answer in the first place. We expect the same result from doing the same operation again, so it isn't really a check.

6 0
2 years ago
Solve the inequality<br> 2(4+2x)25x+5<br> 0 X5-2<br> O x2-2<br> O x3<br> O X23
Sveta_85 [38]
If you’re simplifying it’s 100x^2+200x+5
3 0
3 years ago
In a science class, students water a plant with the same amount of water each day for 28 consecutive days. If the students use a
Luden [163]

Answer::::::::::::::::::::::::::::::::::::

6 0
3 years ago
Read 2 more answers
A triangle has a 90° angle. What type of triangle is it?
CaHeK987 [17]

Answer:

Its a right triangle

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Write a quadratic function in standard form with zeros 1 and -10
Licemer1 [7]

Answer:

f(x)=x^2+9x-10

Step-by-step explanation:

<u>Standard Form of Quadratic Function</u>

The standard form of a quadratic function is:

f(x)=ax^2+bx+c

where a,b, and c are constants.

The factored form of a quadratic equation is:

f(x)=a(x-\alpha)(x-\beta)

Where \alpha and \beta are the roots or zeros of f, and a is constant.

We know the zeros of the function are 1 and -10. The function is:

f(x)=a(x-1)(x-(-10))

f(x)=a(x-1)(x+10)

Operating:

f(x)=a(x^2+10x-x-10)

Joining like terms:

f(x)=a(x^2+9x-10)

Since we are not given any more restrictions, we can choose the value of a=1, thus. the required function is:

\boxed{f(x)=x^2+9x-10}

6 0
3 years ago
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