Answer:
vertex form is y=a(x−h)2+k. To solve this you have to complete the square with the x terms: y= 3x2−12x+4. first isolate the x terms: y−4=3x2−12x. ax2+bx+c to complete the square a=1 and c=(12b)2.
Step-by-step explanation:
vertex form is y=a(x−h)2+k. To solve this you have to complete the square with the x terms: y= 3x2−12x+4. first isolate the x terms: y−4=3x2−12x. ax2+bx+c to complete the square a=1 and c=(12b)2.
Answer:
m = 10 , n = 5
Step-by-step explanation:
using the cosine and tangent ratio in the right triangle and the exact values
cos45° = 
and tan45° = 1 , then
cos45° = 
= 
= ( cross- multiply )
m = 5 × = 5 × 2 = 10
-----------------------------------------
tan45° = 
= 
= 1 , then
n = 5
Answer:
Yez
Step-by-step explanation:
Yes
Answer:
Advance tickets cost $30; same-day tickets cost $35.
Step-by-step explanation:
Let a = the cost of an advance ticket
and s = the cost of a same-day ticket
We have two conditions:
(1) a + s = 65
(2) 15a + 20s = 1150
Subtract a from each side of (1) (3) s = 65 - a
Substitute (3) into (2) 15a + 20(65 - a) = 1150
Distribute the 20 15a + 1300 - 20a = 1150
Combine like terms 1300 - 5a = 1150
Subtract 1300 from each side -5a = -150
Divide each side by -5 (4) a = 30
Substitute (4) into (1) 30 + s = 65
Subtract 30 from each side s = 35
Advance tickets cost $30; same-day tickets cost $35.
Check:
(1) 30 + 35 = 65 (2) 15 × 30 + 20 × 35 = 1150
65 = 65 450 + 700 = 1150
1150 = 1150
Answer:
<h3>2.5secs</h3>
Step-by-step explanation:
Given the height of the ball modeled by the equation h = -16t^2+ 100, where
h is the height
t is in seconds
We can find the time taken by the ball to reach the ground.
The ball reaches the ground when the height h = 0
Substitute h = 0 into the equation and find t;
0 = -16t^2+ 100
16t^2 = 100
t^2 = 100/16
t = √100/16
t = 10/4
t = 2.5secs
Hence the ball reaches the ground after 2.5secs
