I keep getting the wrong answer, I have a test tomorrow, I need some help with it. Thank you!
1 answer:
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Answer:
1.03
Step-by-step explanation:
To find the volume of a prism, find the area of the base and multiply it by the height.
The base is an octagon. The area is found . Substitute a = 0.5.
The volume is 1.21*2.5 = 3.025.
However, there are three holes drilled out half way which each have volume 0.06.
The volume is found as V = πr²h. Substitute r = 0.125 which is half the diameter of 0.25. Since they go half way, the height is h = 1.25.
V = π(0.125)²(1.25) = 0.06.
Since there are 3, they equal 3*0.06 = 0.18.
Subtract this from the volume.
1.21 - 0.18 = 1.03
Answer:
(b) 1.95
Step-by-step explanation:
One of the easiest ways to evaluate an arithmetic expression of almost any kind is to type it into an on-line calculator. Many times, typing it into a search box is equivalent.
<h3>Application</h3>See the attachment for the search box input (at top) and the result. This calculator has the benefit that it <em>always follows the Order of Operations</em> when evaluating an expression. (Not all calculators do.)
ln(7) ≈ 1.95
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<em>Additional comment</em>
If your math course is asking you to evaluate such expressions, you have probably been provided a calculator to use, or given the requirements for a calculator suitable for use in the course.
There are some very nice calculator apps for phone and tablet. Many phones and tablets already come with built-in calculator apps. For the purpose here, you need a "scientific" or "graphing" calculator. A 4-function calculator will not do.
As with any tool, it is always a good idea to read the manual for your calculator and work through any example problems.
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Years ago, handheld calculators were not available, and most desktop calculators were only capable of the basic four arithmetic functions. Finding a logarithm required use of a table of logarithms. Such tables were published in mathematical handbooks, and extracts of those often appeared as appendices in math textbooks used in school.
