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KIM [24]
2 years ago
13

Rewrite! Write an new and equivalent equation that is easier to solve

Mathematics
2 answers:
katrin2010 [14]2 years ago
4 0

\sf{ 7( \sqrt{m+1} - 3)=21}

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

\sf{\sqrt{m+1} - 3)=\frac{21}{7}}

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

\sf{ 7( \sqrt{m+1} - 3)=3}

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

\sf{\sqrt{m+1} =6}

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

Get the power of 2 in both sides.

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

\sf{( \sqrt{m + 1})^2 = 6^2}

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

\sf{m+1=36}

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

\sf{m=35}

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

<u>So the answer is m = 35</u>

Vladimir79 [104]2 years ago
3 0

{\huge{\fcolorbox{yellow}{red}{\orange{\boxed{\boxed{\boxed{\boxed{\underbrace{\overbrace{\mathfrak{\pink{\fcolorbox{green}{blue}{Answer}}}}}}}}}}}}}

\sf 7( \sqrt{m + 1}  - 3) = 21

we will multiply 7 with bracket

\sf 7 \sqrt{m + 1}  - 21 = 21

Now we will take (-21) on LHS to RHS

\sf 7 \sqrt{m + 1}  = 21 + 21 \\  \\  \sf7 \sqrt{m + 1 }  = 42 \\  \\  \sf  \sqrt{m + 1}  =  \frac{42}{7}  \\  \\  \sf  \sqrt{m + 1}  = 6

Now we will do squaring both sides

\sf {( \sqrt{m + 1}) }^{2}  =  {(6)}^{2}  \\  \\  \sf  \red {m + 1 = 36}

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