Answer:
0, for q ≠ 0 and q ≠ 1
Step-by-step explanation:
Assuming q ≠ 0, you want to find the value of x such that ...
q^x = 1
This is solved using logarithms.
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x·log(q) = log(1) = 0
The zero product rule tells us this will have two solutions:
x = 0
log(q) = 0 ⇒ q = 1
If q is not 0 or 1, then its value is 1 when raised to the 0 power. If q is 1, then its value will be 1 when raised to <em>any</em> power.
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<em>Additional comment</em>
The applicable rule of logarithms is ...
log(a^b) = b·log(a)
1/2*2a= 1a
-6b*1/2=-3b
8* 1/2= 4
so 1a-3b+8
Answer:
it's -4 i don't know what you mean by regrouping, sorry
Step-by-step explanation:
Answer:
Below.
Step-by-step explanation:
- tan 2x = -2tanx / (1 - tan^2x)
Using the identity tan^2x = sec^2x - 1 and substituting for tan^2x:
- tan 2x = -2 tanx / (1 - (sec^2x - 1))
= 2 tanx / ( - 1(sec^2x + 2))
= 2 tan x / (sec^2 x - 2)
so we know she has sculptures and paintings, if she sold twice as many paintings as sculptures, that means that for every 2 paintings, she sold 1 sculpture, so the paintings and sculptures are on a 2:1 ratio.
we know she sold a total of 57, so we'll need to split 57 in a 2:1 ratio, we'll simply divide the whole amount of 57 by (2+1) and distribute accordingly.
