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Westkost [7]
3 years ago
13

3/5 plus what other fraction equals to 6

Mathematics
1 answer:
weqwewe [10]3 years ago
3 0

Answer:

27/5 or 5 2/5

Step-by-step explanation:

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the drawing of a building shown below has a scale of 1 inch and 30 feet. What is the actual hdight in feet of the building
34kurt
Given:
1 inch = 30 feet

The drawing of the building of this problem has the height of 1.25 inches and base of 0.75 inches.

Actual height: 
1.25 inches * 30 feet/inch = 37.50 feet

Actual base:
0.75 inches * 30 feet/inch = 22.50 feet
5 0
3 years ago
Please help me ASAP!!!!
Stels [109]

The phrase can be written as:

\lvert x+5\rvert=3

therefore the correct choice is the third one.

7 0
1 year ago
In 1992, Jason bought a gallon of gas for $1.19. Yesterday, he bought a gallon of gas for $2.23. What is the percentage increase
dexar [7]

Answer:

87.3

Step-by-step explanation:

I did the math

8 0
3 years ago
The spinner is equally likely to land on any of the six sections.
andreyandreev [35.5K]

|\Omega|=6\\ |A|=\underbrace{2}_{\text{greater than 4}}+\underbrace{3}_{\text{shaded}}-\underbrace{1}_{\text{shaded 5}}=4\\\\ P(A)=\dfrac{4}{6}=\dfrac{2}{3}

6 0
4 years ago
Read 2 more answers
How far is the portion of her route from A to D? Round to the nearest whole number. Explain. I NEED IT BY TONIGHT SO PLSS SOMEON
inn [45]

9514 1404 393

Answer:

  A to D is about 2087 ft

Step-by-step explanation:

For the portion of the path of interest, the sine and cosine relations apply.

  Sin = Opposite/Hypotenuse

  Cos = Adjacent/Hypotenuse

__

AB is the adjacent side to the angle marked 33°, with hypotenuse 975 ft.

  cos(33°) = AB/(975 ft)

  AB = (975 ft)cos(33°) ≈ 817.70 ft

BC is the opposite side in the same triangle.

  sin(33°) = BC/(975 ft)

  BC = (975 ft)sin(33°) ≈ 531.02 ft

CD is the hypotenuse of the right triangle BCD. The side BC that we know is opposite the given angle, so the sine relation applies.

  sin(46°) = BC/CD

  CD = BC/sin(46°)

  CD = (531.02 ft)/sin(46°) ≈ 738.21 ft

__

Now we know the segments of the path of interest:

  A–D = AB +BC +CD

  A–D = 817.70 ft + 531.02 ft + 738.21 ft = 2086.93 ft

  A–D ≈ 2087 ft

_____

<em>Additional comments</em>

The attachment shows all of the segments computed working counterclockwise from A. The angles in triangle DEF are computed using the Law of Sines from sides DF and DE and angle DEF. Segments EG and GH are computed using the Law of Cosines.

When we get to points F, G, H, we find that there is some inconsistency with the locations that would be computed working clockwise using AB and angle BFA. This inconsistency shows up in an error in the 119° angle in the attached figure.

This means that segments on the back side of the route, along path EFGHA, will vary somewhat depending on how they're computed.

We assume that points B, C, F, G are collinear.

5 0
3 years ago
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