Answer:
Check the explanation
Step-by-step explanation:
Let 
and 
be sample means of white and Jesse denotes are two random variables.
Given that both samples are having normally distributed.
Assume having with mean 
and having mean 
Also we have given the variance is constant
A)
We can test hypothesis as
For this problem
Test statistic is
Where
We have given all information for samples
By calculations we get
s=2.41
T=2.52
Here test statistic is having t-distribution with df=(10+7-2)=15
So p-value is P(t15>2.52)=0.012
Here significance level is 0.05
Since p-value is <0.05 we are rejecting null hypothesis at 95% confidence.
We can conclude that White has significant higher mean than Jesse. This claim we can made at 95% confidence.
Answer:
5/6
Step-by-step explanation:
- 2/3 ÷ 4/5 = ⇒ <em>changing division to multiplication by reciprocal of the second fraction</em>
- 2/3 × 5/4 = ⇒ <em>simplify and multiply numerators and denominators</em>
- 5/6 ⇒ <em>here is the answer</em>
Answer:
-1772
Step-by-step explanation:
The nth term of an arithmetic sequence is expressed as;
Tn = a+(n-1)d
a is the first term
n is the number of terms
d is the common difference
From the sequence
a = 28
d = 8-28 = -12-8 = -20
n =91(since we are looking for the 91st term)
Substrate
T91 = 28+(91-1)(-20)
T91 = 28+90(-20)
T91 = 28-1800
T91 = -1772
Hence the 91st term is -1772
