Since, both the events are independent.
So, P(A+B) = P(A)×P(B)
a) P( Head & Getting a 2 ) = P( head ) × P( Getting a 2 )

b) P( Even number & Tail ) = P( Even number ) × P( Tail )

Hence, this is the required solution.
Answer:
There is a 45.05% probability that the selected person is a right-handed female.
Step-by-step explanation:
We have these following probabilities
A 50% probability that a person is a male
A 50% probability that a person is a female.
A 12.6% probability that a male is left-handed.
A 9.9% probability that a female is left-handed.
If a person is selected at random, to find the probability that the selected person is a right-handed female, one would compute:
50% are female.
9.9% of the females are left-handed, so 100-9.9 = 90.1% of the females are right handed.
So

There is a 45.05% probability that the selected person is a right-handed female.
Answer:
250
Step-by-step explanation:
20% of 250 is 50. 100% of 250 is 250, therefore 20 percent of 250 equals 50.
More simplified explanation: The question is asking if 50 is 20% of a number, what is the number? So we know that 20% is 1/5 of 100%; if we know that 50 is 20% of something, then we would multiply 50 by 5 to get the answer. We would have to multiply 50 by 5 because if 50 is 20% of a number that would mean that 50 is 1/5 of the number we need to find, so to find the number, you to multiply 50 by 5.
Hope this helps!