Answer:
All real numbers are solutions.
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
4(3x+2)=16x+7−4x+1
(4)(3x)+(4)(2)=16x+7+−4x+1(Distribute)
12x+8=16x+7+−4x+1
12x+8=(16x+−4x)+(7+1)(Combine Like Terms)
12x+8=12x+8
12x+8=12x+8
Step 2: Subtract 12x from both sides.
12x+8−12x=12x+8−12x
8=8
Step 3: Subtract 8 from both sides.
8−8=8−8
0=0
The number of possible combinations is given by
... C(18, 3) = 18!/(3!(18-3)!) = 18·17·16/(3·2·1) = 816 . . . . possible combinations
_____
There are 18 ways to choose the first one; 17 ways to choose the second one, and 16 ways to choose the 3rd one. The same 3 students can be chosen in any of 3! = 6 different orders, so the product 18·17·16 must be divided by 6 to get the number of possible combinations in which order doesn't matter.
4.626,5.63,4811,9320.........
Answer:
![[6\frac{1}{6},6\frac{1}{3},6\frac{1}{2},6\frac{2}{3},6\frac{5}{6}]](https://tex.z-dn.net/?f=%5B6%5Cfrac%7B1%7D%7B6%7D%2C6%5Cfrac%7B1%7D%7B3%7D%2C6%5Cfrac%7B1%7D%7B2%7D%2C6%5Cfrac%7B2%7D%7B3%7D%2C6%5Cfrac%7B5%7D%7B6%7D%5D)
Step-by-step explanation:
we have the compound inequality
where
x is a mixed number
so
The solution for the compound inequality are the numbers
![[6\frac{1}{6},6\frac{2}{6},6\frac{3}{6},6\frac{4}{6},6\frac{5}{6}]](https://tex.z-dn.net/?f=%5B6%5Cfrac%7B1%7D%7B6%7D%2C6%5Cfrac%7B2%7D%7B6%7D%2C6%5Cfrac%7B3%7D%7B6%7D%2C6%5Cfrac%7B4%7D%7B6%7D%2C6%5Cfrac%7B5%7D%7B6%7D%5D)
Simplify the numbers
