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iris [78.8K]
3 years ago
11

5,2,4 does this make a triangle

Mathematics
2 answers:
yulyashka [42]3 years ago
6 0

Answer:

Yes

Step-by-step explanation:

Two numbers have to be greater than the other one or it does not make a triangle.

5+2>4, 7>4 true

5+4>2, 9>2 true

4+2>5, 6>5 true

If this helps please mark as brainliest

KonstantinChe [14]3 years ago
6 0
Yes because 5 and 4 are greater than 2.
a2 +b2 = c2
2^2 + 4^2 = 5^2
4 + 16 =25

Pythagorean theorem proves that those side lengths create a triangle as well.
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Need help with Select Expansion or Contraction to correctly describe the type of dilation for each given scale factor.
ad-work [718]

To know if a dilation is an expansion ( bigger) r a contraction ( smaller) ignore the negative sign.

If the number is larger than 1, it is an expansion, if the number is smaller than 1 it is a contraction.


-4 is an expansion

2.5 is an expansion

2/3 is a contraction

-3/4 is a contraction


6 0
4 years ago
I need help with these questions
inysia [295]

Answer:

28. m<A=20°, m<B=70°

32. m<A=103°, m<B=77°

Step-by-step explanation:

complementary angle=a+b=90°

supplementary angle=a+b=180°

28. A+B=90°

      5x+17x+2=90°

      22x+2=90°

      22x=90-2

      22x=88

        22x/22=88/22

      x=88/22=<u>4</u>

m<A=5x=5*4=<u>20°</u>

m<B=17x+2=17*4+2=68+2=<u>70°</u>

         <u>Check</u>

A+B=90°

20+70=90°

<u>90°=90°</u>

32. A+B=180°

     x+11+x-15=180°

     2x-4=180°

     2x=180+4

     2x=184

     2x/2=184/2

     x=184/2

     x=<u>92</u>

m<A=x+11=92+11=<u>103°</u>

m<B=x-15=92-15=<u>77°</u>

     <u>Check</u>

A+B=180°

103+77=180°

<u>180°=180°</u>

6 0
3 years ago
Estimate the measure of ∠PQR to the nearest 10 degree
timurjin [86]

Answer: i’m just guessing but id say 45°??

Step-by-step explanation:

bc it looks like half of 90° and half of 90 is 45

4 0
3 years ago
Read 2 more answers
Consider the surface defined by the equation x3 + y3 + z3 = 3xyz. Use implicit differ- ∂z entiation to find ∂x. (Note z is not a
Aloiza [94]

Answer:    

   \frac{∂z}{∂x}=\frac{(3yz-3x^{2})}{3z^{2} -3xy}

Step-by-step explanation:

Given equation is x^{3}+y^{3}+z^{3}=3xyz ………………(1)

we use derivative formula \frac{d}{dx}(x^{n})  = n x^{n-1}

\frac{d}{dx}(x^{3)}  = 3 x^{2}

\frac{d}{dx}(z^{3)}  = 3 z^{2}

And also apply 'u v' formula

\frac{d}{dx}(uv})  = u\frac{d}{dx}(v)+v\frac{d}{dx}(u)

Differentiating  equation (1) partially with respective to 'x' , we treated 'y' as constant.

(3x^{2} +0+3z^{2}\frac{∂z}{∂x}) =3y(x\frac{∂z}{∂x}+z(1))   ( here y treated as constant so the derivative of constant function is zero in addition but in multiplication the constant is keep as like 'y').

on simplification , we get

(3x^{2} +0+3z^{2}\frac{∂z}{∂x}) =(3yx\frac{∂z}{∂x}+3yz)

again simplification, we get

3z^{2}\frac{∂z}{∂x}- 3yx\frac{∂z}{∂x}=3yz-3x^{2}

taking common '\frac{∂z}{∂x} on left on side , we get

(3z^{2}- 3yx)\frac{∂z}{∂x}=3yz-3x^{2}

dividing '(3z^{2}- 3yx) on both sides, we get

\frac{∂z}{∂x}=\frac{(3yz-3x^{2})}{3z^{2} -3xy}

<u>Final answer</u>:-

\frac{∂z}{∂x}=\frac{(3yz-3x^{2})}{3z^{2} -3xy}

6 0
3 years ago
The water level in a swimming pool decreases from 60 inches to 58.25 inches in one week.
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