(4,-2) and (24,-17) finding the slope from points
1 answer:
Use the equation for the slope:
The two points are equal to (x1, y1) and (x2, y2).
So choose one of your points to be (x1, y1). Let's choose (4, -2). That means x1 = 4 and y1 = -2.
The other point would then be (x2, y2). So x2 = 24 and y2 = -17.
Now put these values in to the equation:
The slope is -3/4.
The two points are equal to (x1, y1) and (x2, y2).
So choose one of your points to be (x1, y1). Let's choose (4, -2). That means x1 = 4 and y1 = -2.
The other point would then be (x2, y2). So x2 = 24 and y2 = -17.
Now put these values in to the equation:
The slope is -3/4.
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∠BDC and ∠AED are right angles, is a piece of additional information is appropriate to prove △ CEA ~ △ CDB
Triangle AEC is shown. Line segment B, D is drawn near point C to form triangle BDC.
Similar triangles, are those triangles which have similar properties,i.e. angles and proportionality of sides.
Image is attached below,
as shown in figure
∡ACE = ∡BCD ( common angle )
∡AED = ∡BDC ( since AE and BD are perpendicular to same line EC and make right angles as E and C)
∡EAC =- ∡DBC ( corresponding angles because AE and BD are parallel lines)
Thus, △CEA ~ △CDB , because of the two perpendiculars AE and BD.
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