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SashulF [63]
3 years ago
10

The width of a rectangle is 1/3 its length, l .

Mathematics
1 answer:
bulgar [2K]3 years ago
5 0
The correct expression for perimeter is <span>2(l+1/3l). If you solve this for 56; </span><span>2(l+1/3l) = 56. You find that l = 21. If l = 21, then the width is 7, and Area = l * w, so the area of the rectangle is 147 square inches.</span>
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The price of gold has increased by 35% per year from 2000. In the year 2000, Harry bought a gold ring for $590. Which of the fol
meriva
The correct choice is A. When something is being increased by a percentage, you add the percentage to 100%, so you add 35% to 100% to make a decimal of 1.35.  Every year the initial value of 590 will be increased by 35%. so the correct choice is A.
3 0
3 years ago
Can you help me please ​
alexira [117]

Answer:

Please check the explanation.

Step-by-step explanation:

Given that

|v|=38

Ф = 120°

<u>Finding the horizontal component</u>

The horizontal component can be obtained using the formula

Vx = |v| cos Ф

     = 38 cos 120°

     = 38 (-0.5)

      = -19

Thus, the  horizontal component is:

Vx = -19

<u>Finding the vertical component</u>

The vertical component can be obtained using the formula

Vy = |v| sin Ф

    = 38 sin 120°

    = 38 (0.86)

    = 32.68

Thus, the vertical component is:

Vy = -19

  • A vector 'v' with magnitude |v| and direction Ф can be written as:

v = |v| cos Ф i + |v| sin Ф j

As

|v|=38

Ф = 120°

Thus, the vector is

v = 38 cos 120° i + 38 sin 120° j

or

v = -19 i + 32.68 j

5 0
3 years ago
7 over 2 as a mixed number ​
ivanzaharov [21]

Answer:

3 1/2

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Please help me out and with work included
irina1246 [14]
Hope that makes sense


3 0
3 years ago
prove that sin theta cos theta = cot theta is not a trigonometric identity by producing a counterexample
Zolol [24]

Answer:

To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.

Begin with the right hand side:

R.H.S = cot θ = \frac{cos \ \theta}{sin \ \theta}

L.H.S = sin θ cos θ

so, sin θ cos θ ≠ \frac{cos \ \theta}{sin \ \theta}

So, the equation is not a trigonometric identity.

=========================================================

<u>Anther solution:</u>

To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.

Assume θ with a value and substitute with it.

Let θ = 45°

So, L.H.S = sin θ cos θ = sin 45° cos 45° = (1/√2) * (1/√2) = 1/2

R.H.S = cot θ = cot 45 = 1

So, L.H.S ≠ R.H.S

So, sin θ cos θ = cot θ is not a trigonometric identity.

5 0
3 years ago
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