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galina1969 [7]
3 years ago
14

Please help this is my last question and I've been waiting 40 minutes

Mathematics
2 answers:
Sophie [7]3 years ago
6 0

Part A:The graph below shows the height of a kicked soccer ball f(x), in feet, depending on the distance from the kicker x, in feet  

X Intercept=(0,0) it represents the time the ball was not kicked at all  

X intercept=(16,0)  

the feet away from the starting point is 16ft the location or distance the ball is away from the starting point once landed.  

Maximum: is 10  

intervals:it increased(0 to 8) decreased (8 to 16)  

when the ball was 8 ft away from the kicker horizontally, it was 10 feet in the air then it landed an additional 8 feet away from the kicker that was 16 feet away one it landed after going a maximum of 10 feet.  

Part B: m=(y2 - y1) / (x2 - x1)  

(x1, y1) (x2, y2)  

(8,10) (13, 7)  

m = (7-10)/(13-8) = -3/5

disa [49]3 years ago
4 0
Check the picture below.

now, notice, each square in the grid is 2 units, so, x = 8, y = 10 and x = 13, y = 5

\bf slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby 
\begin{array}{llll}
average\ rate\\
of\ change
\end{array}\\\\
-------------------------------\\\\
\qquad 
\begin{cases}
x_1=8\\
x_2=13
\end{cases}\implies \cfrac{f(13)-f(8)}{13-8}\implies \cfrac{5-10}{13-8}\implies \cfrac{-5}{5}\implies -1

-1 or -1/1, or -(vertical distance) / (horizontal distance)

the negative means is dropping, and 1/1 means, for every foot going down, it moves farther away from the kicker by 1 foot.

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