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Sveta_85 [38]
3 years ago
8

There were 35,000 hardback copies of a certain novel sold before the paperback version was issued. From the time the first paper

back copy was sold until the last copy of the novel was sold, nine times as many paperback copies as hardback copies were sold. If a total of 448,000 copies of the novel were sold in all, how many paperback copies were sold
Mathematics
1 answer:
bija089 [108]3 years ago
4 0

Answer:

3,717,000

Step-by-step explanation:

The calculation of paperback copies is shown below:-

Let us assume hardback copies is x, so paperback copies will be 9x

now the equation is

35,000 + x + 9x = 448,000

10x = 448,000 - 35,000

10x = 413,000

= \frac{413,000}{10}

= 41,300

Therefore, the paperback copies are

=  9\times 41,300

= 3,717,000

Hence, the paperback copies is 3,717,000

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1.333 the answer I hope help
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the graph of f(x) = 2x 4 shifts five units to the right when it is replaced with the graph of f(x) = 2x − k. what is the value o
vekshin1
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2 years ago
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F(x)=x2+5x-1 is shifted 3 units left the result is g(x) what is g(x)?
Len [333]
Replace the x in  x^2 + 5x - 1 by x+3:-

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3 years ago
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stellarik [79]

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6 0
2 years ago
How do I solve 3+k/14=4
Sedaia [141]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{k = 53}}}}}

Step-by-step explanation:

\bigstar{ \sf{   \:  \: \frac{3 + k}{14} = 4}}

\tt{Step \: 1 \: } : Do cross multiplication

\hookrightarrow{ \sf{3 + k = 4 \times 14}}

\tt{Step \: 2} : Multiply the numbers : 4 and 14

\hookrightarrow{ \sf{3 + k = 56}}

\tt{Step \: 3 \: } Move 3 to right hand side and change it's sign

\hookrightarrow{ \sf{k = 56 - 3}}

\tt{Step \: 4 \: } Subtract 3 from 56

\hookrightarrow{ \sf{k = 53}}

The value of k is 53

Hope I helped!

Best regards! :D

~TheAnimeGirl

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