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Sveta_85 [38]
3 years ago
8

There were 35,000 hardback copies of a certain novel sold before the paperback version was issued. From the time the first paper

back copy was sold until the last copy of the novel was sold, nine times as many paperback copies as hardback copies were sold. If a total of 448,000 copies of the novel were sold in all, how many paperback copies were sold
Mathematics
1 answer:
bija089 [108]3 years ago
4 0

Answer:

3,717,000

Step-by-step explanation:

The calculation of paperback copies is shown below:-

Let us assume hardback copies is x, so paperback copies will be 9x

now the equation is

35,000 + x + 9x = 448,000

10x = 448,000 - 35,000

10x = 413,000

= \frac{413,000}{10}

= 41,300

Therefore, the paperback copies are

=  9\times 41,300

= 3,717,000

Hence, the paperback copies is 3,717,000

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What is the sum of the finite arithmetic series (-5)+0+5+10+ ......+65
Alex17521 [72]

If you want to solve this problem using formulas, there are two important formulas:

t1  =  first term  =  -5          

tn  =  nth term  =  last term  =  -5

n  =  numbr of terms

Sn  =  sum of the n terms

tn  =  t1 + (n - 1)d     --->     65  =  -5 + (n - 1)(5)

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                                          65  =  -10 + 5n

                                          75  =  5n

                                            n  =  15

Sn  =  n(t1 + tn)/2     --->     Sn  =  15(-5 + 65)/2

                                          Sn  =  450


So ur answer rounds up to 450


Letter c

:)

hope i helped 


~Luis

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Hello, i need some help for questions 2-5 please
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<em><u>Answers</u></em><em><u>: </u></em>

<em>4</em><em>.</em><em> </em><em>=</em><em>9.999</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

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