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elena55 [62]
2 years ago
13

Please help I’ll mark some brainlest

Mathematics
1 answer:
lapo4ka [179]2 years ago
4 0
I think it’s 20, the 0 to 4 is 9 and the 5 to 9 is 11, 9 + 11 = 20
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What is the area of this figure?
Leni [432]

Answer:

315

Step-by-step explanation:

5 0
2 years ago
Help please ughhhhhhhh
ahrayia [7]
=P*r*t
=500*4.5%*10
=225
p= 500
r= 4.5%
t= 10
3 0
3 years ago
The diagram shows a 5 cm x 5 cm x 5 cm cube.
Nitella [24]

Answer:

8.7 cm

Step-by-step explanation:

The question is a 2-two-step Pythagoras theorem. (c^2 = a^2 + b^2)

Consider as such, If I were to draw a diagonal line along the base of the cube what is the length of the diagonal line. To find out that we use the theorem. We can substitute a for 5 and b for 5 as well. So

a^2 +b^2 = c^2

5^2 + 5^2 = c^2

25 + 25 = c^2

√50 = c

Then since the line side of the cube is on a 3d angle we need to do the same process again but now using the imaginary diagonal line that we just calculated and the height (5).

a^2 +b^2 = c^2

√50^2 + 5^2 = c^2

50 + 25 = c^2

√75 = c

c = 8.6602...

<em>when rounded to 1 d.p.</em>

c = 8.7

Line AB is 8.7 cm long.

7 0
3 years ago
Please help me with this i don’t understand much
Alexus [3.1K]

Answer:

See below

Step-by-step explanation:

Three lengths will be a triangle only if the sum of two sides is greater than the third side.

19+11 > 17

This is a triangle.

23+28> 52\\51>52\\51 \ngtr 52

This is not a triangle.

9+25> 34\\34>34\\34\ngtr 34

This is not a triangle.

13+14> 22\\27>22

This is a triangle.

8 0
2 years ago
Solve the following for the specified variable<br><br> Z=s/2(P+p); for P
lapo4ka [179]

Answer:

\boxed{\sf P = \frac{2Z}{s} - p}

Step-by-step explanation:

\sf Solve \ for \ P: \\ \sf \implies  Z = \frac{s}{2} (P + p) \\ \\ \sf Z = \frac{s}{2} (P + p) \ is \ equivalent \ to \ \frac{s}{2} (P + p) = Z: \\ \sf \implies \frac{s}{2} (P + p) = Z \\ \\  \sf Divide \ both \ sides \ by \ \frac{s}{2} : \\ \sf \implies P + p = \frac{2Z}{s} \\ \\ \sf Substrate \ p \ from \ both \ sides: \\ \sf \implies P = \frac{2Z}{s} - p

6 0
2 years ago
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