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3 years ago

$18, 000 at 9% compounded semiannually for 6 years

Mathematics

1 answer:

Eddi Din [679]3 years ago

7 0

Answer: $30,525.87

Step-by-step explanation:

$A=P(1+\frac{r}{n})^n^t$

A = Amount

P = Principal

r = rate

n = number of times it is compounded

t = time

$A=18000(1+\frac{0.09}{2})^(^2^)^(^6^) \\A=30,525.87$

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24 is 120% of what number?

laiz [17]

120÷100= 1.2
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24 is 120% of 20

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3 years ago

Please help me and explain the anwser

natita [175]

ANSWER: y=7 is the equation Of the line that passes to through the point (-2,7) and Has a slope of zero.

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2 years ago

Select the correct answer. which expression is equivalent to the given expression? assume the denominator does not equal zero. a

Alexxandr [17]

If the denominator does not equal 0, the equivalent expression of $\frac{14x^4y^6}{7x^8y^2}$ is $\frac{2y^{4}}{x^{4}}$ $\frac{x^{10} y^{14}}{729}$

<h3>How to determine the equivalent expression?</h3>

The expression is given as:

$\frac{14x^4y^6}{7x^8y^2}$

Divide 14 by 7

$\frac{14x^4y^6}{7x^8y^2} = \frac{2x^4y^6}{x^8y^2}$

Apply the law of indices

$\frac{14x^4y^6}{7x^8y^2} = \frac{2y^{6-2}}{x^{8-4}}$

Evaluate the differences in the exponents

$\frac{14x^4y^6}{7x^8y^2} = \frac{2y^{4}}{x^{4}}$

Hence, the equivalent expression of $\frac{14x^4y^6}{7x^8y^2}$ is $\frac{2y^{4}}{x^{4}}$

Read more about equivalent expressions at:

brainly.com/question/2972832

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2 years ago

The roof of the Terminal Tower is 709 feet above ground. A window washer dropped a bucket from the edge of the roof. How many se

Masja [62]

Answer:

6.64 seconds

Step-by-step explanation:

Given that:

Distance between roof of the terminal and ground = 709 feet

A bucket was dropped from the roof.

To find:

The time taken by the bucket to hit the ground?

Solution:

Distance traveled, $s$ = 709 feet

Initial velocity of the bucket, $u$ = 0 feet/sec (because initially it was at rest)

Acceleration of the bucket will be equal to acceleration due to gravity i.e.

$g$ or 32.1741 $ft/sec^{2}$

Let the time taken is $t$ seconds.

Formula for distance is given as:

$s = ut+\dfrac{1}{2}at^2$

Putting all the values:

$709 = 0 (t) + \dfrac{1}{2}(32.1741) t^2\\\Rightarrow 1418 = 32.1741 t^2\\\Rightarrow t^2 = 44.07\\\Rightarrow t \approx \bold{6.64\ sec}$

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3 years ago

Decrease 40 by 15%<br><br> please explain how you got your answer too :)

Anit [1.1K]

So 10 % of 40 is 4
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so 15% is 6
then you have to do 40-6
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8 0

3 years ago

$18, 000 at 9% compounded semiannually for 6 years​

$18, 000 at 9% compounded semiannually for 6 years