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3 years ago

7

What is the GCF of two prime Numbers ??Give Me A Example?

1 answer:

xeze [42]3 years ago

7 0

It's 1. Factors of prime numbers are 1 or themselves. Examples: Factors of 5 are 1 and 5, factors of 7 are 1 and 7. The only factor common to prime numbers is 1. I hope i helped :3

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If 2.5 mol of dust particles were laid end to end along the equator, how many times would they encircle the planet? The circumfe

Natalka [10]

Answer:

They encircle the planet $3.76\times 10^{11}$ times.

Step-by-step explanation:

Consider the provided information.

We have 2.5 mole of dust particles and the Avogadro's number is $6.022\times 10^{23}$

Thus, the number of dust particles is:

$2.5\times 6.022\times 10^{23}=15.055\times 10^{23}$

Diameter of a dust particles is 10μm and the circumference of earth is 40,076 km.

Convert the measurement in meters.

Diameter: $10\mu m\times \frac{10^{-6}m}{\mu m} =10^{-5}m$

If we line up the particles the distance they could cover is:

$15.055\times 10^{23}\times 10^{-5}=15.055\times 10^{18}=1.5055\times 10^{19}$

Circumference in meters:

$40,076km\times \frac{1000m}{1km}=40,076,000 m$

Therefore,

$\frac{1.5055\times 10^{19}}{40,076,000} = 3.76\times 10^{11}$

Hence, they encircle the planet $3.76\times 10^{11}$ times.

8 0

3 years ago

Simplify the following expression 8x+9-6x-7

mamaluj [8]

8x + -6x = 2x 2 + 2x

4 0

2 years ago

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Four girls have 2.20 to share equally. How much money will each girl get?

Nata [24]

Answer:

0,55

Step-by-step explanation:

8 0

2 years ago

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How to solve the system of equation 500y-600x=2800 , 400y-400x=2400 by elimination

tatiyna

Answer:

$x=2$ and $y=8$

Step-by-step explanation:

Given:

Equation 1:

$500y-600x=2800$

Simplifying the above equation by dividing both sides by 100

$\frac{500y-600x}{100}=\frac{2800}{100}$

$\frac{500y}{100}-\frac{600x}{100}=28\\\\5y-6x=28$

Equation 2:

$400y-400x=2400$

Simplifying the above equation by dividing both sides by 400.

$\frac{400y-400x}{400}=\frac{2400}{400}$

$\frac{400y}{400}-\frac{400x}{400}=6\\\\y-x=6$

Now the system of equation is:

(1a) $5y-6x=28$

(2a) $y-x=6$

Solving by elimination

Multiplying equation (2a) with $-5$

$-5(y-x)=-5\times 6$

(2b) $-5y+5x=-30$

Adding equations (1a) and (2b) in order to eliminate $y$

$5y-6x=28$

+ $-5y+5x=-30$

We get $-x=-2$

∴ $x=2$

Plugging $x=2$ in equation (2a).

$y-2=6$

Adding $2$ both sides.

$y-2+2=6+2$

∴ $y=8$

7 0

3 years ago

What is the distance from the point (−3, −b, c) to the origin?

lord [1]

Answer:

$\sqrt{9+b^2+c^2}\,\text{units}$

Step-by-step explanation:

The distance formula tells you the distance d between the points (0, 0, 0) and (-3, -b, c) is ...

d = √((x2 -x1)² +(y2 -y1)² +(z2 -z1)²) = √((-3-0)² +(-b-0)² +(c-0)²)

= √(9 +b² +c²)

4 0

3 years ago

Read 2 more answers