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Anarel [89]
4 years ago
8

You make a large bowl of salad to share with your friends. Your sister eats 1/3 of it before they come over. You want to divide

the leftover salad evenly among six friends.What fraction of the original salad does each friend receive?
Mathematics
1 answer:
Elodia [21]4 years ago
5 0
You change the 2/3 into 4/6 and do it again so it would be 8/12 then keep ding that till you get the awnswer
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Give the digits in the ones place and the hundredths place.<br> 53.19
Kobotan [32]
The ones place is 3 and the hundredths place is 9. Always remember, on the left side of the point starts with ones followed be tens, but in the right side of the point it starts with tenths followed by hundredth.
4 0
3 years ago
Find angle Picture below
iren [92.7K]

Answer:

14°

Step-by-step explanation:

Need 1 more brainliest

3 0
3 years ago
BD=BC, BD= 5x +26, BC= 2x+1, and AC = 43, find AB
Lostsunrise [7]
Imagine that points A, B, C and D are collinear and appears in that order from the left to the right. You want to find the measure of the first line segment AB. First, let's find the value of x.

BD = BC
5x + 26 = 2x + 1
5x - 2x = 1 - 26
3x = -25
x = -8.33

2(-8.33) + 1 = -15.67
So, BD=BC= -15.67

To find AB, the solution is as follows:
AC = AB + BC
43 = AB + (-15.67)
AB = 58.67

8 0
3 years ago
I NEED HELP AGAIN PLEASE
Troyanec [42]

Answer:106

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
(4.1.4) Let X and Y be Bernoulli random variables. Let Z = X + Y. a. Show that if X and Y cannot both be equal to 1, then Z is a
Fynjy0 [20]

Step-by-step explanation:

Given that,

a)

X ~ Bernoulli (p_x) and Y ~ Bernoulli (y_x)

X + Y = Z

The possible value for Z are Z = 0 when X = 0 and Y = 0

and Z = 1 when X = 0 and Y = 1 or when X = 1 and Y = 0

If X and Y can not be both equal to 1 , then the probability mass function of the random variable Z takes on the value of 0 for any value of Z other than 0 and 1,

Therefore Z is a Bernoulli random variable

b)

If X and Y can not be both equal to  1

then,

p_z = P(X=1 or Y=1)\\

p_z = P(X=1)+P(Y=1)-P(=1 and Y =1)

p_z = P(x=1)+P(Y=1)\\\\p_z=p_x+p_y

c)

If both X = 1 and Y = 1 then Z = 2

The possible values of the random variable Z are 0, 1 and 2.

since a  Bernoulli variable should be take on only values 0 and 1 the random variable Z does not have Bernoulli distribution

7 0
3 years ago
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