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Allisa [31]
2 years ago
10

-28 + 2x = -18 x=? Solve for x

Mathematics
2 answers:
Novay_Z [31]2 years ago
7 0

Answer:

5

Step-by-step explanation:

2 x 5 = 10

-28 + 10 = -18

so the answer is 5

SpyIntel [72]2 years ago
5 0

Answer:

x = 5

Step-by-step explanation:

-28 + 2x = -18

-18 + 28 = 10 / 2 = 5

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Find the volume of a triangular prisms with base height 4 width 7 and height 10. Please hurry!
Dimas [21]

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Step-by-step explanation:

4 0
3 years ago
7/8 greater than or less than 2/4
Vaselesa [24]

Answer:

greater than

Step-by-step explanation:

7/8 is greater than 4/8

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3 years ago
Find the distance from the point to the given plane. (−8, 6, 4), x − 2y − 4z = 8
Nikitich [7]
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5 0
3 years ago
List all possible rational roots. Then use synthetic division to confirm which rational roots exist:
Kisachek [45]

Answer:

\boxed{(1) \, x = \, \pm \dfrac{1}{2}, \pm 1, \pm2, \pm \dfrac{5}{2}, \pm 5, \pm 10; (2) \, x = -2}

Step-by-step explanation:

2x³+ 6x² - x - 10 = 0

(1) Possible roots

The Rational Roots Theorem states that, if a polynomial has any rational roots, they will have the form p/q, where p is a factor of the constant term  and q is a factor of the leading coefficient.

\text{Possible rational root} = \dfrac{ p }{ q } = \dfrac{\text{factor of constant term}}{\text{factor of leading coefficient}}

In your function, the constant term is -10 and the leading coefficient is 2, so

\text{Possible root} = \dfrac{\text{factor of 10}}{\text{factor of 2}}

Factors of 10 = ±1, ±2, ±5, ±10

Factors of 2 = ±1, ±2

\text{Possible roots are } \large \boxed{\mathbf{x = \pm \dfrac{1}{2}, \pm 1, \pm2, \pm \dfrac{5}{2}, \pm 5, \pm 10}}

(2) Synthetic division

Rather than work through all 12 possibilities, I will do one that works.

\begin{array}{r|rrrr}-2 & 2 & 6 & -1 & -10\\& & -4& -4 & 10\\& 2 & 2& -5 & 0\\\end{array}

So, x = -2 is a root, and the quotient is 2x² + 2x - 5.

(3) Check for other rational roots

2x² + 2x - 5 = 0

D = b² - 4ac =2²- 4(2)(-5) = 4 + 40 = 44

√44 = 2√11, which is irrational.

Since irrational roots come in pairs, the cubic equation has two real, irrational roots and one rational root at x = -2.

6 0
3 years ago
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