A vertical line that the graph of a function approaches but never intersects. The correct option is B.
<h3>When do we get vertical asymptote for a function?</h3>
Suppose that we have the function f(x) such that it is continuous for all input values < a or > a and have got the values of f(x) going to infinity or -ve infinity (from either side of x = a) as x goes near a, and is not defined at x = a, then at that point, there can be constructed a vertical line x = a and it will be called as vertical asymptote for f(x) at x = a
A vertical asymptote can be described as a vertical line that the graph of a function approaches but never intersects.
Hence, the correct option is B.
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Answer:
Step by Step Solution
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
6*x+11-(21)=0
Step by step solution :
STEP
1
:
Pulling out like terms
1.1 Pull out like factors :
6x - 10 = 2 • (3x - 5)
Equation at the end of step
1
:
STEP
2
:
Equations which are never true:
2.1 Solve : 2 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation:
2.2 Solve : 3x-5 = 0
Add 5 to both sides of the equation :
3x = 5
Divide both sides of the equation by 3:
x = 5/3 = 1.667
One solution was found :
x = 5/3 = 1.667
Answer:
Or:
Step-by-step explanation:
We want to write the equation of a line that passes through the points (-6, 5) and (3, -5) in point-slope form.
Point-slope form is given by:
Thus, first, we need to find the slope. We can use the slope formula:
Next, we can use either of the two given points. I'll use (-6, 5). So, let (-6, 5) be (<em>x₁, y₁</em>). Substitute:
Or, fully simplified:
Using the other point, we will acquire:
Or, simplified:
Answer:
1. sum of term = 465
2. nth term of the AP = 30n - 10
Step-by-step explanation:
1. The sum of all natural number from 1 to 30 can be computed as follows. The first term a = 1 and the common difference d = 1 . Therefore
sum of term = n/2(a + l)
where
a = 1
l = last term = 30
n = number of term
sum of term = 30/2(1 + 30)
sum of term = 15(31)
sum of term = 465
2.The nth term of the sequence can be gotten below. The sequence is 20, 50, 80 ......
The first term which is a is equals to 20. The common difference is 50 - 20 or 80 - 50 = 30. Therefore;
a = 20
d = 30
nth term of an AP = a + (n - 1)d
nth term of an AP = 20 + (n - 1)30
nth term of an AP = 20 + 30n - 30
nth term of the AP = 30n - 10
The nth term formula can be used to find the next term progressively. where n = number of term
The sequence will be 20, 50, 80, 110, 140, 170, 200..............
