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inessss [21]
3 years ago
6

Which statement shows how two polynomials 3x + 6 and 5x2 − 4x demonstrate the closure property when multiplied?

Mathematics
2 answers:
Ira Lisetskai [31]3 years ago
8 0

Answer:

15x^3+18x^2-24x

Step-by-step explanation:

it is a polynomial

Novosadov [1.4K]3 years ago
5 0

Answer:

15x^3+18x^2-24x is a polynomial.

B is correct

Step-by-step explanation:

Given: 3x+6 and 5x^2-4x

There are two polynomial with each has two term.

Using closure property multiplied both polynomial.

  • If multiply two polynomial then result must be a polynomial with higher degree of previous two.

Product of 3x+6 and 5x^2-4x

\Rightarrow (3x+6)(5x^2-4x)

\Rightarrow 3x\cdot 5x^2-3x\cdot 4x+6\cdot 5x^2-4x\cdot 6

\Rightarrow 15x^3-12x^2+30x^2-24x

Combine the like terms

\Rightarrow 15x^3+18x^2-24x

This is a polynomial with degree 3

Hence, The product of 3x+6 and 5x^2-4x is a polynomial.

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Amy makes the following statement:
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I do not understand
Pie

Answer:

2500 m^3/1 m^2

Step-by-step explanation:

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An Epson inkjet printer ad advertises that the black ink cartridge will provide enough ink for an average of 245 pages. Assume t
Neko [114]

Answer:

35.2% probability that the sample mean will be 246 pages or more

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 245 \sigma = 15, n = 33, s = \frac{15}{\sqrt{33}} = 2.61

What the probability that the sample mean will be 246 pages or more?

This is 1 subtracted by the pvalue of Z when X = 246. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{246 - 245}{2.61}

Z = 0.38

Z = 0.38 has a pvalue of 0.6480.

1 - 0.6480 = 0.3520

35.2% probability that the sample mean will be 246 pages or more

4 0
3 years ago
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