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Leya [2.2K]
3 years ago
5

Ray cuts out a figure that has 4 equal sides and no right angles. What is the best name for the figure?

Mathematics
3 answers:
BartSMP [9]3 years ago
5 0
The answer is a circle
BaLLatris [955]3 years ago
5 0
It’s a trapezoid... hope this helps
katovenus [111]3 years ago
3 0
It’s a trapezoid... hope this helps
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22/5 times 2 times 1/3
LUCKY_DIMON [66]

Answer:

44/15 or maybe 2 14/15

Step-by-step explanation:

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3 years ago
Help I need to know What is the volume of this cylinder?
Likurg_2 [28]

Answer:

V =4923.52 mm^3

Step-by-step explanation:

The volume of a cylinder is

V = pi r^2h

We need to get the radius

r = d/2 = 28/2 = 14

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8 0
3 years ago
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valkas [14]
I think the answer might be B
6 0
2 years ago
Population Growth The population P (in thousands) of Oriando,Florida from 1980 through 2009 can be modeled by p = 130e0.0205t,wh
svetoff [14.1K]

Answer: a) 236,000.

b) 2021

Step-by-step explanation:

Given : Population Growth The population P (in thousands) of Oriando,Florida from 1980 through 2009 can be modeled by p = 130e^{0.0205t}    (1)

where t = 0 corresponds to 1980.

Then , for 2009

t= 2009-1980=29

a. ⇒The population of Phoenix in 2009 =  p = 130e^{0.0205(29)}

p = 130e^{0.5945}

p =130(1.81212465608)=235.57620529\approx236

Hence, the population of Orlando in 2009 was about 236,000.

b) Substitute p= 300 in (1) , we get

300 = 130e^{0.0205t}

2.3077= e^{0.0205t} (Divide both sides by 130)

Taking Natural log on both sides,

\ln(2.3077) = 0.0205t\\\\\Rightarrow\ t=\dfrac{\ln(2.3077)}{0.0205}

t=\dfrac{0.836251357528}{0.0205}=40.7927491477\approx41

Hence, The year Orlando will have a population of 300,000 =1980+41 =2021

6 0
3 years ago
Maya deposits $5000 into a checking account that pays 0.75% annual interest compounded monthly. What will be the balance after 8
Nana76 [90]

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$5000\\ r=rate\to 0.75\%\to \frac{0.75}{100}\dotfill &0.0075\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years\dotfill &8 \end{cases} \\\\\\ A=5000\left(1+\frac{0.0075}{12}\right)^{12\cdot 8}\implies A=5000(1.000625)^{96}\implies A\approx 5309.08

5 0
2 years ago
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