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Nataliya [291]
4 years ago
11

MATH HELP PLEASE cos x = sin 34° What is the value of x? x = __°

Mathematics
1 answer:
yawa3891 [41]4 years ago
6 0
Cos x=sin34
sin(90-x)=sin34
90-x=34
x=56
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Help plz , math equation !!
Ugo [173]

Answer:

We are given the table of a linear function

Since we have to find the equation of the function in the slope-intercept form,

we require the slope as well as the y-intercept

<u>Finding the slope:</u>

We know that slope of a line is Rise / Run

Since from the graph, we notice that the difference of 2 consecutive x-coordinates is 1

Hence, we have the x-coordinates at an interval of 1 and since the slope of a line is defined as the units ascended by the line after covering 1 unit in the x-coordinate

change in y = y_{n} - y_{n-1}       (where n is the number of row in the table)

change in y = 31 - 23

change in y = 8 = Rise

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Slope = Rise / Run

Slope = 8 / 1

Slope  = 8

<u>Finding the y-intercept:</u>

We need the y-coordinate at x = 0

Going up from the third row, we notice that for every unit decreased in the x-coordinate , 8 units of the y-coordinate are decreased (since the slope =8)

In that case, the y-coordinate of every decreased x-coordinate will be 8 less than the last one

so we can say that the y-coordinate of x = 1 will be 8 less than 23 since x=1 is one less than x = 2

similarly, we can also say that the y-coordinate of x = 0 will be 8 less than (23-8) since x = 0 is one less than x = 1

Therefore, the y-coordinate at x =0

y = (23-8-8)

y-intercept  = 7

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We need to write the equation in the form:

y = ax + b (where a is the slope of the line and b is the y-intercept)

Replacing the known values, we get

y = 8x + 7

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4 years ago
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yawa3891 [41]

Answer:  24\sqrt{3}in^2 or  41.56in^2

Step-by-step explanation:

You can find the area of a regular hexagon with the following formula:

A_{(hexagon)}=\frac{3\sqrt{3}s^2}{2}

Where "s" is any side of the regular hexagon.

For this hexagon you know that the length of each side is 4 inches. Then, you must substitute s=4in into the formula  A_{(hexagon)}=\frac{3\sqrt{3}s^2}{2}.

Therefore, the area of this regular hexagon is:

 A_{(hexagon)}=\frac{3\sqrt{3}(4in)^2}{2}

 A_{(hexagon)}=24\sqrt{3}in^2 or A_{(hexagon)}=41.56in^2

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4 years ago
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slavikrds [6]
D
An acute angle is less than 90 degrees 
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Find x if QRSTU is a regular pentagon.<br> (8x + 12)
kotykmax [81]

Answer:

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Step-by-step explanation:

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Thus, x = 66°.

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