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Vikki [24]
2 years ago
15

9x - 7i < 3 (3x - 7u)

Mathematics
1 answer:
nata0808 [166]2 years ago
6 0

Answer:

Step-by-step explanation:

9x - 7i < 3(3x - 7i)

9x - 7i < 9x - 21i

-7i < -21i

14i < 0i < 0

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If the 9th term of an ap is 1/7 and the 7th term os 1/9 find the 63rd term
Mnenie [13.5K]

Answer:

a_{63} = 1

Step-by-step explanation:

The n th term of an arithmetic progression is

a_{n} = a + (n - 1)d

where a is the first term and d the common difference

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a_{9} = a + 8d = \frac{1}{7} → (1)

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Subtract (2) from (1) term by term

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Substitute this value into (2) and solve for a

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Hence

a_{63} = \frac{1}{63} + \frac{62}{63} = 1


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3 years ago
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