Answer:
y-determinant = 2
Step-by-step explanation:
Given the following system of equation:
Let's represent it using a matrix:
![\left[\begin{array}{ccc}1&2\\1&-3\end{array}\right] = \left[\begin{array}{ccc}5\\7\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%5C%5C1%26-3%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%5C%5C7%5Cend%7Barray%7D%5Cright%5D)
The y‐numerator determinant is formed by taking the constant terms from the system and placing them in the y‐coefficient positions and retaining the x‐coefficients. Then:
![\left[\begin{array}{ccc}1&5\\1&7\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%265%5C%5C1%267%5Cend%7Barray%7D%5Cright%5D%20)
y-determinant = (1)(7) - (5)(1) = 2.
Therefore, the y-determinant = 2
I think the answer is d. The slope of AC=Slope of DF.
Hope this helped☺☺
Answer:
52 if im wrong sorry :(
Step-by-step explanation:
Answer:
x=1
Explain:
y=2x^2−4x+1
dy/dx=4x-4
The line of symmetry will be where the curve turns (due to the nature of the
x^2 graph.
This is also when the gradient of the curve is 0.
Therefore, let
dy/dx=0
This forms an equation such that:
4x−4=0
solve for x,
x=1
and line of symmetry falls on the line
x=1
Answer: step-by-step
Step-by-step explanation:
answer: 10
to solve you have to follow PEMDAS
